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amid [387]
3 years ago
8

Calculate the molarity of 153.3g of H2SO4 in 1.290L of solution

Chemistry
1 answer:
Ksenya-84 [330]3 years ago
3 0
Molar mass H₂SO₄ = 98.0 g/mol

Volume = 1.290 L 

number of moles:

153.3 / 98 => 1.564 moles

M = n / V

M = 1.564 / 1.290

M = 1.212 mol/L

hope this helps!
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madreJ [45]

Answer:

See below!

Explanation:

For the chemical formula, you need to have enough of each atom so that the charge is zero.

Aluminum has a +3 charge, and fluorine has a -1 charge.  Since the charge has to be zero, you need three fluorines, giving you AlF₃.

Barium has a +2 charge, and oxygen has a -2 charge.  Since the charges are equal in magnitude but opposite in sign, you only need one of each atom giving you BaO.

The name of the ionic compound will be the metal and then the nonmetal.  When putting the nonmetal in, change the ending to "-ide".  For example "chlorine" would be "chloride.

CaCl₂  ==>  calcium chloride

Ga₂S₃  ==>  gallium sulfide

K₃N  ==>  potassium nitride

AlF₃ ==>  aluminum fluoride

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3 years ago
Nucleophilicity is a kinetic property. A higher nucleophilicity indicates that the nucleophile will easily donate its electrons
lord [1]

The rate constant (K) is related to activation energy (Ea), frequency factor (A) and temperature (T) in Kelvin by the equation

R = molar gas constant

K = A(e^(-Ea/RT))

Taking natural log of both sides

In K = In A - (Ea/RT)

In K = (-Ea/R)(1/T) + In A

Comparing this to the equation of a straight line; y = mx + c

y = In K, slope, m = (-Ea/R), x = (1/T) and intercept, c = In A

a) From the question, m = (-Ea/R) = -1.10 × (10^4) K

(-Ea/R) = -1.10 × (10^4) = -11000

R = 8.314 J/K.mol

Ea = -11000 × 8.314 = 91454 J/mol = 91.454 KJ/mol

b) c = In A = 33.5

A = e^33.5 = (3.54 × (10^14))/s

c) K = A(e^(-Ea/RT))

A = (3.54 × (10^14))/s, Ea = 91454 J/mol, T = 25°C = 298.15 K, R = 8.314 J/K.mol

K = (3.54 × (10^14))(e^(-91454/(8.314×298.15))) = 0.0336/s

QED!

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A solid, a liquid or a gas.
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Answer:

₂He⁴  

Explanation:

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Properties of alpha radiation:

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

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₉₂U²³⁸   →   ₉₀Th²³⁴  + ₂He⁴  + energy

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