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Natalija [7]
3 years ago
5

Why does sin30° equal 1/2?

Mathematics
2 answers:
gtnhenbr [62]3 years ago
6 0

Step-by-step explanation:

it's easy to prove in any right triangle with a 30° angle, the side opposite to that angle is half the hypotenuse. CA (1/2)BC, CA/BC=1/2

Dmitriy789 [7]3 years ago
6 0

Step-by-step explanation:

Take an equilateral triangle of side.

Bisec it through a vertex and the midpoint of the opposite side.

You now have two right-angled triangles with angels 30° , 60°, 90° with the edge opposite the 30° of length 1/2 and hypotenuse 1. So

sin (30°) = 1/2/1= 1/2.

<u>Answer</u><u>:</u><u> </u><u> </u>The right angled triangle you describe has angels of 45 degrees, not 30 degrees.

What you proved is sin 45 = 1\2 , which is correct.

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Vaselesa [24]
So 3/8 + 4/8 + 5/8 + 7/8 + 1 2/8 =


3 5/8
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Please help me with this
enot [183]

Answer:

∠AMX=72°

Step-by-step explanation:

we know that

An isosceles triangles has two equal sides and two equal interior angles

In the isosceles triangle MAX

we have that

XA=MA

and ∠AXM= ∠AMX -----> angles base    

we have that

∠AXM=72°

therefore

∠AMX=72°

7 0
3 years ago
Find f(2) and f(3).<br> f(1) = 3<br> f(n) = 7f(n = 1)
Kay [80]

Answer:

do it got a picture

on the edge2020

Step-by-step explanation:

4 0
2 years ago
A park is 4 times as long as its wide. If the distance around the park is12.5kilometers, what is the are of the park
Lilit [14]
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(4x+x)×2×2=12.5
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3 0
3 years ago
Which of the following is an even function g(x) = (x – 1)2 + 1g(x) = 2x2 + 1g(x) = 4x + 2g(x) = 2x
GuDViN [60]
An even function can be reflected about the y axis and map onto itself
example: y=x^2

an odd function can be reflected about the origin and map onto itself
example: y=x^3


a simple test is the following

if f(x) is even then f(-x)=f(x)
if f(x) is odd then f(-x)=-f(x)


so

even function
subsitute -x for each and see if we get the same function
remember to fully expand these

g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original one

g(x)=(x-1)^2+1
g(-x)=(-x-1)^2+1
g(-x)=(1)(x+1)^2+1
g(-x)=x^2+2x+1+1
g(-x)=x^2+2x+2
not same because the original has -2x
not even


g(x)=2x^2+1
g(-x)=2(-x)^2+1
g(-x)=2x^2+1
same, it's even

g(x)=4x+2
g(-x)=4(-x)+2
g(-x)=-4x+2
not the same, not even

g(x)=2x
g(-x)=2(-x)
g(-x)=-2x
not same, not even



g(x)=2x²+1 is the even function
8 0
3 years ago
Read 2 more answers
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