3x-4y=16, solve for y

Mathematics

2 answers:

storchak [24]3 years ago

7 0

Answer:

y = −3/4x + 4

Step-by-step explanation:

3x - 4y = 16

Subtract 3x from both sides of the equation.

4y = 16 − 3x

Divide each term by 4 and simplify.

y = 4 − 3/4x

Rewrite in slope-intercept form.

y = −3/4x + 4

Hope that helps!

Gnesinka [82]3 years ago

5 0

Answer: y= 3/4x-4

To solve this you must subtract 3x to have -4y by itself.
—> -4y = -3x+16

Then we want to isolate y so we divide -4 to all of our equation and should be left with:
—> y = 3/4x-4

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If two distinct lines intersect, which is NOT necessarily true? A) The lines are not parallel. B) The lines are perpendicular. C

SVEN [57.7K]

Answer:

B is not necessarily true

Step-by-step explanation:

A) This is always true

B) This is not necessarily true

When two lines intersect, they form angles at the intersection as D says, but that does not mean that the angle will always be 90 degrees as is required for the two intersecting lines to be perpendicular

C) This is always true

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3 years ago

Read 2 more answers

2x + 3(x +3) + (x + 6)

Volgvan

For this case we must simplify the following expression:

$2x + 3 (x + 3) + (x + 6)$