Question

Hi how was your day can you help please

Answer 1

Hi there!

$\huge\boxed{=27}$

$\frac{3^{2}*(2^{3}+4)}{2^2}$

Use the order of operations to solve. Begin by evaluating the inside of the parenthesis.

Evalute 2³ = 8:

$\frac{3^{2}*(8+4)}{2^2}$

Simplify:

$\frac{3^{2}*(12)}{2^2}$

Evaluate each power. 3² = (3 × 3) = 9, and 2² = (2 × 2) = 4:

$\frac{9*(12)}{4}$

Simplify:

$\frac{108}{4} = 27$