All categories

3 years ago

Sam's Grades

Mathematics

1 answer:

Julli [10]3 years ago

3 0

Answer:

90-

Step-by-step explanation:

Bc A-

You might be interested in

What is 6÷102?? for math

notka56 [123]

0.05882352941
Or just 0.05

7 0

3 years ago

How do you show six ways to add 6, 7 and 8?

raketka [301]

6+7+8 6+8+7 7+6+8 8+7+6 7+8+6 and 8+6+7

5 0

4 years ago

Read 2 more answers

Jenna Is 4 Years Older Than Her Sister. The Sum Of Jenna's Age And Her Sister's Age Is 32. How Old Is Jenna?

Fiesta28 [93]

Jenna is 18, her sister is 14
18+14=32

5 0

3 years ago

Read 2 more answers

Based on the Fundamental Theorem of Algebra, how many complex roots does each of the following equations have? Write your answer

Galina-37 [17]

According to the fundamental theorem of algebra, every polynomial of degree n has n complex zeroes.

Part A:

Given

$x(x^2-4)(x^2+16)=0 \\ \\ \Rightarrow x(x^4+12x^2-64)=0 \\ \\ \Rightarrow x^5+12x^3-64x=0$

Thus, the given polynomial is of degree 5 and hence has 5 omplrex roots.

Part B:

Given

$(x^2+4)(x+5)^2 = 0 \\ \\ \Rightarrow(x^2+4)(x^2+10x+25)=0 \\ \\ \Rightarrow x^4+10x^3+25x^2+4x^2+40x+100=0 \\ \\ \Rightarrow x^4+10x^3+29x^2+40x+100=0$

Thus, the polynomial is of degree 4 and hence has 4 complex roots.

Part C:

Given

$x^6-4x^5-24x^2+10x-3=0$

Thus, the given polynomial is of degree 6 and hence has 6 complex roots.

Part D:

Given

$x^7+128=0$

Thus, the given polynomial is of degree 7 and hence has 7 complex roots.

Part E:

Given

$(x^3+9)(x^2-4)=0 \\ \\ \Rightarrow x^5-4x^3+9x^2-36=0$

Thus, the given polynomial is of degree 5 and hence has 5 complex roots.

4 0

3 years ago

Because of the high heat and low humidity in the summer in Death Valley, California, a visitor requires about one quart of water

Helen [10]

Answer:

The answer to your question is mass = 8.73 kg

Step-by-step explanation:

Data

1 quart ----- 2 mi

density = 0.99 g/ml

total distance = 30 km

Process

1.- Convert 2 mi to km

1 mi ------------------- 1.61 km

2 mi ------------------ x

x = (2 x 1.61)/1

x = 3.22 km

2.- Calculate the quarts drank

1 quart --------------------- 3.22 km

x --------------------- 30 km

x = (30 x 1)/3.22

x = 9.32 quarts

3.- Convert quarts to milliliters

1 quart --------------------- 946.35 ml

9.32 quart ------------------- x

x = (9.32 x 946.35) / 1

x = 8817 ml

4.- Calculate the grams of water

density = mass / volume

mass = volume x density

-Substitution

mass = 8817 x 0.99 g/ml

-Result

mass = 8729 g

5.- Convert to kg

mass = 8729/1000 kg

mass = 8.73 kg

5 0

3 years ago

Read 2 more answers