Which specific NASA goal did Apollo 9’s mission focus on?
2 answers:
You might be interested in
X(x + 3) + 34 = (x + 5)(x + 2)
First, expand to remove parentheses.
Second, add '2x + 5x' to get '7x'.
Third, cancel out '
' on both sides.
Fourth, subtract '3x' from both sides.
Fifth, subtract '7x - 3x' to get '4x'.
Sixth, subtract '10' from both sides.
Seventh, subtract '34 - 10' to get '24'.
Eighth, divide both sides by '4', leaving the 'x' by itself.
Ninth, since '24 ÷ 4 = 6', simplify the fraction to '6'.
Tenth, switch your sides to get the answer.
Answer: x = 6
First, expand to remove parentheses.
Second, add '2x + 5x' to get '7x'.
Third, cancel out '
Fourth, subtract '3x' from both sides.
Fifth, subtract '7x - 3x' to get '4x'.
Sixth, subtract '10' from both sides.
Seventh, subtract '34 - 10' to get '24'.
Eighth, divide both sides by '4', leaving the 'x' by itself.
Ninth, since '24 ÷ 4 = 6', simplify the fraction to '6'.
Tenth, switch your sides to get the answer.
Answer: x = 6
9514 1404 393
Answer:
- 4/13 h ≈ 0.308 h
- 22 9/13 km ≈ 22.7 km
Step-by-step explanation:
Mary and Amaruk are starting 35 -15 = 20 km apart. Their closing speed is 40 +25 = 65 km/h. The time it will take to close the gap between them is ...
t = (20 km)/(65 km/h) = 20/65 h = 4/13 h ≈ 0.308 h
They will pass each other after 4/13 hours, about 18 minutes 28 seconds.
__
In that time, Mary will have increased her distance from Hall Beach by ...
d = (4/13 h)(25 km/h) = 100/13 km = 7 9/13 km
Her distance from Hall Beach when she passes Amaruk will be ...
15 km + 7 9/13 km = 22 9/13 km ≈ 22.7 km . . . . . distance from Hall Beach
