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dsp73
3 years ago
5

Which specific NASA goal did Apollo 9’s mission focus on?

Mathematics
2 answers:
gogolik [260]3 years ago
8 0

Answer:

Creating technology for moon flight

Step-by-step explanation:

I took the assignment

atroni [7]3 years ago
5 0
Apollo 9's main purpose was to qualify the LM for crewed lunar flight, demonstrating, among other things, that it could perform the maneuvers in space that would be needed for a lunar landing, including docking with the CSM.
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HELP ME PLEASE!!! I’ll mark brainly
mixas84 [53]

Answer:

yes

Step-by-step explanation:

8 0
3 years ago
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What is the slope of the line that passes through (-2,-2) and (3,-1)?
JulsSmile [24]

Answer:

+1/5

Step-by-step explanation:

3 0
3 years ago
I don't know how to solve this. How would I solve this? Thanks!!!!
Afina-wow [57]

Answer:

x = 11 units

Step-by-step explanation:

Area of triangle = (base + base 2) * h *1/2

so (7 + x )* 7 * 1/2 = 63

63 x 2 = 126

126 / 7 = 18

18-7 = x

x = 11

Check

(7+11)* 7 * 1/2

18* 7 = 126

126 x 0.5 = 63

CORRECT!

(p.s., tell me if wrong :P)

6 0
3 years ago
Rewrite each fraction in simplest form using the GCF of the numerator and denominator.
Elanso [62]

Answer:

\sf 6. \quad \dfrac{7}{10}

\sf 7. \quad \dfrac{5}{17}

Step-by-step explanation:

<h3><u>Question 6</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

  • 42 = 2 × 3 × 7
  • 60 = 2 × 2 × 3 × 5

42 and 60 share one 2 and one 3 in common.

Multiply them together to get the GCF:  2 × 3 = 6.

Therefore, 6 is the GCF of 42 and 60.

Divide the numerator and the denominator by the found GCF:

\implies \sf \dfrac{42 \div 6}{60 \div 6}=\dfrac{7}{10}

<h3><u>Question 7</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

  • 80 = 2 × 2 × 2 × 2 × 5
  • 272 = 2 × 2 × 2 × 2 × 17

80 and 272 share four 2s in common.

Multiply them together to get the GCF:  2 × 2 × 2 × 2 = 16.

Therefore, 16 is the GCF of 80 and 272.

Divide the numerator and the denominator by the found GCF:

\implies \sf \dfrac{80 \div 16}{272 \div 16}=\dfrac{5}{17}

5 0
2 years ago
Read 2 more answers
Youssef can either way from his home to his workplace or ride his bicycle. he walks at a pace of 1 block per min, but he can tra
alex41 [277]

Youssef lives 15 blocks away from his work

<em><u>Solution:</u></em>

Given that Youssef can either way from his home to his workplace or ride his bicycle

Let "x" be number of blocks away from work Youssef works

<u><em>Case 1: walking</em></u>

He walks at a pace of 1 block per min

Therefore,

1 block = 1 minute

Thus to cross "x" blocks he takes "x" minutes

<em><u>Case 2: Bicycle</u></em>

He can travel 1 block in 20 sec on his bicycle

We know that,

To convert seconds to minute, divide the time value by 60

\rightarrow 20 seconds = \frac{20}{60} minutes = \frac{1}{3} minutes

Thus he takes 1/3 minutes for 1 block

So to cross "x" blocks he will take \frac{x}{3} minutes

Given that it takes youssef 10 min longer to walk to work than to ride his bike

This means difference between time taken to cross "x" blocks by walking and ride by bicycle is 10 minutes

\rightarrow x - \frac{x}{3} = 10\\\\\rightarrow \frac{3x - x}{3} = 10\\\\\rightarrow \frac{2x}{3} = 10\\\\\rightarrow x = \frac{30}{2}\\\\\rightarrow x = 15

Thus he lives 15 blocks away from his work

4 0
3 years ago
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