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igomit [66]
3 years ago
6

How do I find mean median range iqr and standard deviation ​

Mathematics
1 answer:
ycow [4]3 years ago
6 0

Answer: to find the mean add the numbers that were given then Divine by the amount of numbers you added. To find the median put all the numbers in numerical order and pick the middle one if it is an even amount of numbers than you pick the number exactly halfway between the two middle. To find the range you see how many numbers are repeated in which ever number is repeated the most amount of times that is the range.

Step-by-step explanation:

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3 0
3 years ago
Find the product (8/6n-4)(9n^2-4)
Leokris [45]

Answer:

4(3n+2) or 12n+8

Step-by-step explanation:

Given expression is:

(\frac{8}{6n-4})(9n^{2}-4)

The numerator of the fraction will be multiplied with 9n^2- 4

So, Multiplication will give us:

=\frac{8(9n^2-4)}{6n-4}

We can simplify the expression before multiplication.

The numerator will be broken down using the formula:

a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}

We can take 2 as common factor from denominator

=\frac{8(3n-2)(3n+2)}{2(3n-2)}\\After\ cutting\\= 4(3n+2)

Hence the product is 4(3n+2) or 12n+8 ..

6 0
3 years ago
Why is it important to have high<br> quality audio files
Sever21 [200]

Answer:

TO HEAR BETTER

Because as quality increases the tone increases

6 0
3 years ago
Read 2 more answers
Which point is the solution to the following system of equations? x2 + y2 = 13 2x - y = 4
Anit [1.1K]
There are two solutions.
.. (3, 2)
.. (0.2, -3.6)

_____
If you're choosing possibilities from a list, trying them in the equations usually gives quick results.

4 0
3 years ago
Read 2 more answers
Determine the horizontal, vertical, and slant asymptotes: y=x2+2x-3/x-7
densk [106]

Answer:

  • vertical asymptote: x = 7
  • slant asymptote: y = x+9

Step-by-step explanation:

The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.

There is no horizontal asymptote because the numerator is of higher degree than the denominator.

When you divide the numerator by the denominator, you get ...

  y = (x +9) +60/(x -7)

Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.

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3 years ago
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