Y = 3x − 8

Mathematics

1 answer:

Nana76 [90]2 years ago

3 0

Answer:

A. You would first plot the y intercept. The first equation would be (0,-8) and the second equation is (0,-11). Then you would plot the slope. For the first equation, from (0,-8), you would move up 3 plots and right 1 plot. For the second equation, from (0,-11), you would move up 9 plots and right 1 plot.

B. The solution to the pair of inequalities is (1/2, -13/2). That is the intersection and point of the two lines. You would need to graph the two lines (see part A answer) and then find the intersection.

Hope this helps!

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2 years ago

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Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

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Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$