The answer to your question is:
It is a quadratic equation in 'x', with 'n' mistakenly typed in the second term..
Although you didn't ask for the solutions to the equation, I'm already here
so I might as well go through it and find them:
<span><u>3x² - 2x - 5 = 0</u></span>
In terms of the generic quadratic formula:
A = 3
B = -2
C = -5
Plug those into the quadratic formula, and you discover that
<u>x = -1</u>
and
<u>x = ⁵/₃</u>
To Calculate the cost of <span>The cost of fertilizing, we need to Calculate first the Area of the Triangle.
</span>the Area of the Triangle = 1/2 x base x altitude = 1/2 x (14+√17) x 68 = 524.08 <span>square foot
</span>The cost of fertilizing = the cost of the square foot x the total area = 0.25x524.08 = 131 <span>$</span>
They are variables they can equal anything. it is just an example of two different fractions who's numbers are unknown.
to get the equation of any straight line, we simply need two points off of it, well, let's use the provided values hmmm

