-1/3x-4/3y=2
1/3x-2/3y=4
First realize that the coefficient of x is -1/3 and 1/3 which can be eliminated with addition
Adding the two equations together gets
-6/3y=6
Simplify
-2y=6
y=-3
Substitute back into original equation
1/3x-2/3(-3)=4
1/3x+2=4
1/3x=2
x=6
Answer
x=6, y=-3
Check answer
-1/3(6)-4/3(-3) =?= 2
-2+4=2
2=2
Done!
Answer:
(-6, -5).
Step-by-step explanation:
If there is a zero between the integers there will be a change of sign of f(x).
x^3 + 5x^2 - x - 6
f(1) = 1 + 5 - 1 - 6 = -1
f(-1) = -1 + 5 + 1 - 6 = -1
f(2) = 8 + 20 - 2 -6 = 20
There' a change of sign between f(1) and f(2) so there is a zero between (1, 2).
f(-2) = -8 + 20 + 2 - 6= 6
So there is also a zero between -1 and -2. (-2, -1)
F(-4) = 14, f(-5) = -1 = change of sign so there is also a zero in (-5,-4)
f(-6) = -36 - no change in sign between -5 and -6.
Answer:
63500000
Step-by-step explanation:
63500000
There is the answer hope you like it I also added the steps
