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dalvyx [7]
3 years ago
9

Ten times the sum of half a number and 6 is 8​

Mathematics
2 answers:
Ksju [112]3 years ago
8 0
7 is the right answer!!!!!!!!!!!!!!!!!!!
Digiron [165]3 years ago
3 0

Answer:

I think it's 7

Step-by-step explanation:

I'm guessing I think

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I don’t understand this one
Masja [62]

Answer:

  see below

Step-by-step explanation:

Put -1 where x is in each expression and evaluate it.

__

You will find that the expression is zero when the numerator is zero. And you will find the numerator is zero when it has a factor that is equivalent to ...

  (x +1)

Substituting x=-1 into this factor makes it be ...

  (-1 +1) = 0

__

Evaluating the first expression, we have ...

\dfrac{4(x+1)}{(4x+5)}=\dfrac{4(-1+1)}{4(-1)+5}=\dfrac{4\cdot 0}{1}=0

This first expression is one you want to "check."

You can see that the reason the expression is zero is that x+1 has a sum of zero. You can look for that same sum in the other expressions. (The tricky one is the one with the factor (x -(-1)). You know, of course, that -(-1) = +1.)

5 0
3 years ago
What is 3000 divided by 25<br> *Brainliest Offered*
Tema [17]
3000 ÷ 25 = 120

Check: 
120(25) = 3000 <------------------True
3 0
3 years ago
Read 2 more answers
if a teacher has 24 students total and she selects a student to go on a fieldtrip and she picks a boy to attend the fieldtrip an
Savatey [412]
I don't know how many boys are in the classroom?
5 0
3 years ago
Whats the answer to this one?
natta225 [31]
The answers are P: (-4,3) Q: (4,-3)
5 0
3 years ago
Evaluate 6j+23+k/l−3, when j=3, k=7, and l=33.<br><br> Enter your answer in the box.
melomori [17]

Answer:

37 7/33 or 37.212

Step-by-step explanation:

6j + 23 + k/l - 3

If j = 3, k = 7, and l = 33:

6 × 3 + 23 + 7/33 - 3

= 18 + 22 + 7/33 - 3

= 40 + 7/33 - 3

= 40 7/33 - 3

NOTE: Because 40 and 3 are whole numbers, 3 will be subtracted from 40.

= 37 7/33 or 37.212

3 0
3 years ago
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