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Katena32 [7]
3 years ago
8

What is the scale factor?

Mathematics
2 answers:
satela [25.4K]3 years ago
8 0
A scale factor in math is the ratio between corresponding measurements of an object and a reorientation
Alborosie3 years ago
7 0

Answer:

hope like it

Step-by-step explanation:

A scale factor is usually a decimal which scales, or multiplies, some quantity. In the equation y = Cx, C is the scale factor for x. C is also the coefficient of x, and may be called the constant of proportionality of y to x. For example, doubling distances corresponds to a scale factor of two for distance, while cutting a cake in half results in pieces with a scale factor for volume of one half. The basic equation for it is image over preimage.

In the field of measurements, the scale factor of an instrument is sometimes referred to as sensitivity. The ratio of any two corresponding lengths in two similar geometric figures is also called a scale.

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The diagonal of a rectangle is 25 in. The width is 15 in. What is the area of the rectangle?
Nana76 [90]

Answer:

375 in² is the answer.

Step-by-step explanation:

Are of rectangle= area of 2 triangle

= 1/2*25*15+1/2*25*15

=187.5+187.5

=375 in²

7 0
2 years ago
What is a tenth of a decimal ?
trapecia [35]
One decimal place to the left decimal point is the place.
8 0
3 years ago
Please help i need to write out my work to so please tell me how to show it
Anarel [89]
For the first one write 9 divided by 2 gives your your radius an it’s 3.5. the formula is 2 x 3.14 x radius and that gives you 21.98.

the 2nd one is 2 x 3.14 x 9 = 56.52

the 3rd is 2 x 3.14 x 5= 31.4

formula is always 2 x 3.14 (or pie) x radius

to get your radius from your diameter you do your diameter divided by 2
3 0
2 years ago
Read 2 more answers
PLS 40 points
Pavlova-9 [17]
<h2>2x+y=2</h2>

Step-by-step explanation:

Let p1 be the point (-1,4)

Let p2 be the point (3,-4)

The equation of the line passing through two points p1=(x_{1},y_{1})

and p2=(x_{2},y_{2}) is \frac{y-y_{1}}{x-x_{1}} =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

substituting p1,p2 in the above equation yields

\frac{y-4}{x-(-1)}=\frac{-4-4}{3-(-1)}

which when simplified gives \frac{y-4}{x+1}=\frac{-8}{4}

which when further simplified gives 2x+y=2

5 0
3 years ago
ABCD is a square of side 3, and E and F are the mid points of sides AB and BC respectively. What is the area of the quadrilatera
Dima020 [189]
Given : - Square ABCD with side 3.  E and F as midpoints.
To find : - area of EBFD

Solution : - We have, area of square ABCD = 3 x 3 = 9 units.

Thus, (ar)EBFD = ar ABCD - ar DAE - arDCF

arDAE = 1/2 x base x height

=1/2 x 1.5 x 3 ( AE is 1/2 of AB = 1.5, DA is altitude)
= 2.25

arDFC = 1/2 x base x height 
= 1/2 x 1.5 x 3 (FC is 1/2 of BC, DC is altitude)
= 2.25

Thus, (ar) EBFD = arABCD - arDAE - arDCF

= 9 - 2.25 - 2.25

= 4.5 units.

Thus, area of quad EBFD is 4.5 units.  
7 0
3 years ago
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