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andreev551 [17]
3 years ago
6

Martin is interested in the effects of different kinds of instruction on videogame performance. Martin asks 30 college freshmen

to each play 1 hour of Ratchet and Klank. Participants are randomly assigned to one of three instruction groups: (1) complete the tasks as quickly as possible, (2) conserve as much health as possible (i.e., play more carefully), or (3) find gold bolts (worth lots of money in equipment and ammunition). Obviously, even in a single instruction group, not all players will obtain the same final score. These differences in an instruction group reflect:
Mathematics
1 answer:
777dan777 [17]3 years ago
5 0

Answer:

Between - groups variance

Step-by-step explanation:

From the question we see that the college freshmen are assigned to one of the three given groups. This means that they are exposed to different experimental conditions and thus it means that the variation differs as a result of different experimental conditions between the groups.

Thus, these differences reflect between - group variance.

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PLEASE HELP WITH QUESTIONS 11-14 ASAP!!!!!!!!
zysi [14]

Answer:

11) mean=2   12) median=2   13)range =4  

Step-by-step explanation:

11) the set is

0,0,1,1,1,2,2,2,2,2,3,3,3,4,4

so add all these which will give you 30 and then divide that by how many numbers are there in the set which there are 15, so 30 divided 15 =2

12) arrange numbers from smallest to largest and the number exactly in the middle is the median

13)biggest number-smallest number

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3 years ago
HELP ME WITH THESE TWO PLS !! I'LL GIVE BRAINLIEST
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6 0
3 years ago
What is the sum of the first 70 consecutive odd numbers? Explain.
expeople1 [14]

The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)

The second sum is simply the sum of N ones:

\underbrace{1+1+1\ldots+1}_{N\text{ times}}=N

So, the final result is

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2

which ends the proof.

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3 years ago
Please solve with explanation
OverLord2011 [107]

Real life scenarios of acute angles are:

  • Sighting a ball from the top of a building at an angle of 55 degrees.
  • The angle between two adjacent vanes of a fan that has 6 vanes

<h3>What are acute angles?</h3>

As a general rule, an acute angle, x is represented as: x < 90

This means that acute angles are less than 90 degrees.

<h3>The real life scenarios</h3>

The real life scenarios that involve acute angles are scenarios that whose measure of angle is less than 90 degrees.

Sample of the real life scenarios that satisfy the above definition are:

  • Sighting a ball from the top of a building at an angle of 55 degrees.
  • The angle between two adjacent vanes of a fan that has 6 vanes

Read more about acute angles at:

brainly.com/question/3217512

#SPJ1

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