Question

Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of the gym. The lawn is rectangular, and the length is 5 feet more than twice the width. The perimeter of the lawn is 250 feet. Homework Help ✎
Use the 5-D Process to find the dimensions of the lawn.

Use the dimensions you calculated in part (a) to find the area of the lawn.

What are the answers and how do i solve it thank you

Answer 1

Answer: The dimension of the lawn = 85 × 40

Area of the lawn = 3250 square feet

Step-by-step explanation:

Let x represents the width of the rectangle,

Then According to the question,

The length of the rectangle = 2 x + 5

Also it is given that the perimeter of the rectangle = 250 feet.

But we know that the perimeter of the rectangle = 2 × ( length + width)

Thus, the perimeter of the rectangle = 2( 2x+5+x) = 2(3x+5) = 6x+10

If x = 30,  the perimeter of the rectangle = 6 × 30 + 10 = 190 < 250

Thus, x ≠ 10.

If x = 50,  the perimeter of the rectangle = 6 × 50 + 10 = 310 > 250

Thus, x ≠ 50

If x  = 40, the  the perimeter of the rectangle = 6 × 40 + 10 = 250 = 250

Thus, x = 40

Therefore, the width of the rectangle, x  = 40 feet.

And, the length of the rectangle, 2 x + 5 = 2 × 40 + 5 = 85 feet.

1) The dimension of the rectangle = 85 × 40

2)The area of the rectangle = length × width = 85 × 40  = 3250 square feet.