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defon
3 years ago
15

Jackie bought

Biology
1 answer:
Hoochie [10]3 years ago
6 0

Answer:

we cannot understand your question, if you could please re-word it I would be happy to help.

Explanation:

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The frequency of the recessive allele for the left handle will be in this case equal to q^2 = 0.25 >> q = 0.5.

<h3>What is the Hardy Weinberg principle?</h3>

The Hardy Weinberg principle is a model used in population genetics to estimate genotypic and allele frequencies.

The Hardy Weinberg principle states that the sum of the dominant allele and the recessive allele in a population is equal to 1 (p + q = 1).

This principle also states p2 + q2 + 2pq = 1, where p^2 is the dominant homo-zygous allele, 2pq the heterozygous frequency and  q^2 the recessive homo-zygous frequency.

In this case, 9 individuals represent 25% (q^2 = 0.25), thereby the feecuency of q is equal to √0.25 = 0.5.

Learn more about the HW principle here:

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