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mixas84 [53]
3 years ago
9

Please help. answer my last question​

Mathematics
1 answer:
viva [34]3 years ago
8 0

What is your last question?

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3. A gumball machine with 200 gumballs has 40
murzikaleks [220]

Answer:

3/8 or 0.375 or 37.5%

Step-by-step explanation:

red, blue, yellow gumballs = 125 total

green gumballs= 75

75 green/200 total gumballs

simplified = 3/8

5 0
3 years ago
Read 2 more answers
Evaluate the following expression using the values given: Find 5x - 3y-zifx -2,y 2 and z 3 0 -19 o 19 0 13 0 -13
MAVERICK [17]

Answer:

A. -19

Step-by-step explanation:

5x - 3y - z

5 (-2) - 3 (2) - 3

-10 - 6 - 3

-16 - 3

-19

6 0
3 years ago
Never mind I found out pls don't comment
antoniya [11.8K]

Break horizontally in middle

Area of rectangle

  • LB
  • 20(10)
  • 200ft²

Area of triangle

  • 1/2BH
  • 1/2(20-10)(20-10)
  • 1/2(10)²
  • 100/2
  • 50ft²

Total area

  • 200+50
  • 250ft²
5 0
2 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
4 years ago
2. The area of a trapezium is 1080
mezya [45]

Answer:

Therefore, the distance (height) is 24cm.

<u>Brainliest plzzzzz</u>

Step-by-step explanation:

Area of trapezium = 1/2 × (a+b) × h

*a and b are the parallel lengths

Now we are going to find the distance, which is height (also known as 'h').

First, substitute the given values into the equation.

1080 = 1/2 × (55.6 + 34.4) × h

Move the 1/2 over to 1080 and divide.

1080 ÷ 1/2 = (55.6 + 34.4) × h

2160 = (55.6 + 34.4) × h

Add the numbers in the brackets.

2160 = 90 × h

Move 90 over to 2160 and divide.

2160 ÷ 90 = h

24 = h

6 0
3 years ago
Read 2 more answers
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