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Ksju [112]
3 years ago
13

Choose a method you prefer to solve for a system of linear equations. 2x + 4y = -4 2x-y=6

Mathematics
1 answer:
Artyom0805 [142]3 years ago
7 0

Answer:

Elimination

x = 2

y = -2

Step-by-step explanation:

Elimination

2x + 4y = -4

2x - y = 6

Subtract the second equation from the first

5y = -10

Divide both sides by 5

y = -2

---------------------

Substitute for y = -2 in the second equation

2x - -2 = 6

2x + 2 = 6

subtract 2 from both sides

2x = 4

Divide both sides by 2

x = 2

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4 0
3 years ago
Help please thank you!
monitta

Answer:

• multiplied by 4p: (x -h)² +4pk = 0

• zeros for k > 0: none

• zeros for k = 0: one

• zeros for k < 0: two

Step-by-step explanation:

a) Multiplying by 4p removes the 1/(4p) factor from the squared term, but adds a factor of 4p to the k term. (It has no effect on the subsequent questions or answers, so we wonder why we're doing this.) The result is ...

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b) The value of k is the vertical location of the vertex of the parabola with respect to the x-axis. The parabola opens upward, so for k > 0, the parabola does not cross the x-axis, and the number of real zeros is zero. (There are two complex zeros.)

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d) As in part b, the value of k defines the vertex location. When it is negative, the vertex of the parabola is below the x-axis. Since the parabola opens upward, both branches will cross the x-axis, resulting in two real zeros.

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The attached graph shows a parabola with p=1/4 and h=2. The values shown for k are +1, 0, and -1. The coordinates of the real zeros are shown.

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