3 years ago

If x is going towards negative infinity (LEFT),

1 answer:

5 0

Your y values should not move in any direction whatsoever because you just said your x values are only moving

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Bogdan [553]

Answer:

$x = \dfrac{5}{2} \pm {\dfrac{\sqrt{57}}{2}$

Step-by-step explanation:

$x^2 - 5x = 8$

$x^2 - 5x + \dfrac{25}{4} = 8 + \dfrac{25}{4}$

$(x - \dfrac{5}{2})^2 = \dfrac{57}{4}$

$x - \dfrac{5}{2} = \pm \sqrt{\frac{57}{4}}$

$x = \dfrac{5}{2} \pm {\dfrac{\sqrt{57}}{2}$

5 0

3 years ago

Nesterboy [21]

The answer is A 3,6,7

5 0

3 years ago

Yakvenalex [24]

the answer for the second problem is x=99 degrees and y= 261 degrees

dunno the first problem :/

3 0

3 years ago

Annette [7]

The answer is 22, good luck on you work

7 0

4 years ago

OleMash [197]

The opposite way that the normal y=x would be!

4 0

3 years ago