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Nataly_w [17]
3 years ago
13

Circle is divided into 20 equal parts. What is the angle measure of three of those parts?

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0
First, imagine a circle divided into 4 quarters
than you may use the following proportion

angle measure ------- part of circle
90^0 - -----\frac14\\ x \ \ ------\frac3{20}\\ \\ \frac14x=90^0\cdot\frac3{20}\\ \frac14x=\frac{270}{20}\\ \frac14x=\frac{27}2\ \ \ \ |\cdot4\\ x=\frac{27}2\cdot4\\ x=\frac{108}2\\ \boxed{x=54\ degrees}
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Juan has 4 1/2 gallons of blue paint. Each wall in his house will need 3/4 of a gallon of paint. How many walls can Juan paint b
Lostsunrise [7]
We know that

<span>4 1/2 gallons-------> (4+2+1)/2-----> 9/2 gallons
</span>
1 <span> wall in the house will need --------> 3/4 of a gallon of paint
</span> X wall-----------------------------------> 9/2 gallons
x=(9/2)/(3/4)----> 9*4/2*3-----> 36/6----> 6 walls

the answer is
6 walls
6 0
3 years ago
Adult tickets to a play cost $24. Tickets for children cost $18. Tickets for a group of 13 people cost $282. Write and solve a s
Elan Coil [88]
Let number of Adult ticket be x
and number of Child ticket be y
so
$282 = $24x + $18y.
:)

4 0
3 years ago
Read 2 more answers
The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.
VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

\int\limits^2_{-1} {(f(x) - g(x))} \, dx

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx

We know that:

\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}

\int\limits^{}_{} {1} \, dx = x

\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}

Then our integral is:

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2}  + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3}  + (-1) - \frac{(-1)^2}{2}  )

The right side is equal to:

(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6

The bounded area is 5 + 5/6 square units.

3 0
3 years ago
Montserrat is training for her first race. In her first training week she runs 3 km, and in the second training week she runs 3.
ArbitrLikvidat [17]

Answer:8

Step-by-step explanation:

0.5*10=5

3+5=8

8 0
3 years ago
kim needed 9 inches of trim for every kitchen towel she was making. she made 25 towels. how many feet of trim did kim use?
NNADVOKAT [17]
25 x 9= 225
225 is your answer
6 0
3 years ago
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