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4 years ago

Circle is divided into 20 equal parts. What is the angle measure of three of those parts?

1 answer:

Nutka1998 [239]4 years ago

7 0

First, imagine a circle divided into 4 quarters
than you may use the following proportion

angle measure ------- part of circle
$90^0 - -----\frac14\\ x \ \ ------\frac3{20}\\ \\ \frac14x=90^0\cdot\frac3{20}\\ \frac14x=\frac{270}{20}\\ \frac14x=\frac{27}2\ \ \ \ |\cdot4\\ x=\frac{27}2\cdot4\\ x=\frac{108}2\\ \boxed{x=54\ degrees}$

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Show how to solve the problem 378 times 6 using place value with regrouping. Explain how you knew when to regroup

kkurt [141]

378 x 6 as (300 x 6) + (70 x 6) + (8 x 6) = 1800 + 420 + 48 = 2268

4 0

3 years ago

Read 2 more answers

90 POINTS I need help ASAP on everything but part A (WILL GIVE BRAINLIEST) Roller Coaster Crew Ray and Kelsey have summer intern

maxonik [38]

Answer:

Part A) Kesley is correct

Part B) g'(x)=3x2-2x-4

Part C) Graph attached

Part D) Explained

Step-by-step explanation:

Part A)

Kelsey is correct because no. of 0s in a 3rd degree polynomial be 3. which means the no. of intercepts will be 3. Thus Ray is incorrect as no. of 0s and x-intercept are similar thing.

Further a graph is attached of g(x) = x3 − x2 − 4x + 4 to describe the key features of g(x), including the end behavior. We can see that there are 3 x-intercepts at (2,0), (1,0) and (-2,0) which validates the point of Kelsey that the function can have as many as 3 zeros only because it is 3rd degree polynomial.

Part B)

As the second part of the new coaster is a parabola. To create a unique parabola in the pattern f(x) = ax2 + bx + c

finding derivative of g(x) picked in Part A) i.e.

g(x) = x3 − x2 − 4x + 4

g'(x)=3x2-2x-4

Graph of above is also attache.

From the graph we can see that its downwards directed parabola having vertex at (0.33, -4.33)

x-intercept at -0.87 and 1.53

y-intercept at (0,-4)

The axis of symmetry equation is a vertical line around which the parabola is symmetric is given by equation of a vertical line that passes through the vertex i.e. x=0.33

Part C)

Graph 3 is also attached.

Part D)

For a 15 seconds ad campaign, following features can be included:

Roller coaster that have a three rise

two sharp dips

the 2nd dip goes more deeper than the first one!

6 0

3 years ago

If anybody now this pls help my homework due TOMORROW

Nezavi [6.7K]

Answer:

Part A: D. $y = (x + 1)(x+3)\\$

Part B: C. $3x(x-3) = 0\\$

Step-by-step explanation:

For part A) we just have to plug in 0 for x and solve for y until we find the equation that says 3 is the value for y when x is 0. For purposes of speeding up the process the correct answer is D. I will show how to check for it now.

The equation: $y = (x + 1)(x+3)$

Now plug in 0 for x.

$y = (0 + 1)(0+3)\\$

Now solve.

y = (1)(3)

y = 3

This proves that this is the correct answer.

For part B) we just have to plug in the give values for x separately and check for each value of x that it equals 0. For the purpose of speeding up the process the correct answer is C. I will show how to check for it now.

The equation: $3x(x-3) = 0$

Now plug in x for 0 and solve:

$3* 0 (0-3) = 0\\$

$0(-3) = 0\\$

$0 =0\\$

This equation is true, now we check for the other value of x, 3.

$3*3(3-3) = 0\\$

$9(0) = 0\\$

$0 =0\\$

This is also true so that means this is the correct answer.

6 0

4 years ago

PLEASE HELP! much appreciated :D Find the value of x.

Georgia [21]

Answer:

Step-by-step explanation:

8 0

3 years ago

P(x) = x + 1x² – 34x + 343 d(x)= x + 9

Feliz [49]

Answer:

$x=\frac{9}{d-1},\:P=\frac{-297d+378}{\left(d-1\right)^2}+343$

Step-by-step explanation:

Let us start by isolating x for dx = x + 9.

dx - x = x + 9 - x > dx - x = 9.

Factor out the common term of x > x(d - 1) = 9.

Now divide both sides by d - 1 > $\frac{x\left(d-1\right)}{d-1}=\frac{9}{d-1};\quad \:d\ne \:1$ . Go ahead and simplify.

$x=\frac{9}{d-1};\quad \:d\ne \:1$ .

Now, $\mathrm{For\:}P=x+1x^2-34x+343, \mathrm{Subsititute\:}x=\frac{9}{d-1}$ .

$P=\frac{9}{d-1}+1\cdot \left(\frac{9}{d-1}\right)^2-34\cdot \frac{9}{d-1}+343$ .

Group the like terms... $1\cdot \left(\frac{9}{d-1}\right)^2+\frac{9}{d-1}-34\cdot \frac{9}{d-1}+343$ .

$\mathrm{Add\:similar\:elements:}\:\frac{9}{d-1}-34\cdot \frac{9}{d-1}=-33\cdot \frac{9}{d-1}$ > $1\cdot \left(\frac{9}{d-1}\right)^2-33\cdot \frac{9}{d-1}+343$ .

Now for $1\cdot \left(\frac{9}{d-1}\right)^2 > \mathrm{Apply\:exponent\:rule}: \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c} > \frac{9^2}{\left(d-1\right)^2} = 1\cdot \frac{9^2}{\left(d-1\right)^2}$ .

$\mathrm{Multiply:}\:1\cdot \frac{9^2}{\left(d-1\right)^2}=\frac{9^2}{\left(d-1\right)^2}$ .

Now for $33\cdot \frac{9}{d-1} > \mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} > \frac{9\cdot \:33}{d-1} > \frac{297}{d-1}$ .

Thus we then get $\frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}+343$ .

Now we want to combine fractions. $\frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}$ .

$\mathrm{Compute\:an\:expression\:comprised\:of\:factors\:that\:appear\:either\:in\:}\left(d-1\right)^2\mathrm{\:or\:}d-1 > This\: is \:the\:LCM > \left(d-1\right)^2$

$\mathrm{For}\:\frac{297}{d-1}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:d-1 > \frac{297}{d-1}=\frac{297\left(d-1\right)}{\left(d-1\right)\left(d-1\right)}=\frac{297\left(d-1\right)}{\left(d-1\right)^2}$

$\frac{9^2}{\left(d-1\right)^2}-\frac{297\left(d-1\right)}{\left(d-1\right)^2} > \mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}> \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$\frac{9^2-297\left(d-1\right)}{\left(d-1\right)^2} > 9^2=81 > \frac{81-297\left(d-1\right)}{\left(d-1\right)^2}$ .

Expand $81-297\left(d-1\right) > -297\left(d-1\right) > \mathrm{Apply\:the\:distributive\:law}: \:a\left(b-c\right)=ab-ac$ .

$-297d-\left(-297\right)\cdot \:1 > \mathrm{Apply\:minus-plus\:rules} > -\left(-a\right)=a > -297d+297\cdot \:1$ .

$\mathrm{Multiply\:the\:numbers:}\:297\cdot \:1=297 > -297d+297 > 81-297d+297 > \mathrm{Add\:the\:numbers:}\:81+297=378 > -297d+378 > \frac{-297d+378}{\left(d-1\right)^2}$

Therefore $P=\frac{-297d+378}{\left(d-1\right)^2}+343$ .

Hope this helps!

5 0

4 years ago