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Finger [1]
3 years ago
12

These box plots show daily low temperatures for a sample of days in two

Mathematics
2 answers:
Elan Coil [88]3 years ago
8 0

Answer:

The answer is B.

Step-by-step explanation:

As you can see, box plot A is symmetrical so that applies to answers A and B. However, box B is very skewed to the right which makes it positively skewed so answer B is the only one that matches the correct description of the two box and whisker plots.

Montano1993 [528]3 years ago
6 0

Answer: B. The distribution for town A is symmetric, but the distribution for

town B is positively skewed.

Step-by-step explanation:

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What is the equation of a line with a y-intercept of -3 and a slope of - 4/5?
ElenaW [278]
I think it’s D not sure good luck though!
7 0
3 years ago
I need help plz I have a time test plz
Ksivusya [100]

Answer:

interest = $600

Step-by-step explanation:

for simple interest,

I = PTR/100

Principal (P) = $5000

Time (T) = 3 YEARS

Rate(R) = 4%

therefore, Interest (I) = $5000 × 3 × 4 / 100

                                  = $ 600

3 0
3 years ago
2x + 3 + 4x + 6 + 12x + 18 = 477<br><br> Please answer with solving steps. Thanks guys :)
dybincka [34]

Answer:

x= 25

Step-by-step explanation:

2x + 3 + 4x + 6 + 12x + 18 = 477

FIRST combine like terms

take all "x"

2+4+12= 18x

take all whole numbers

3+6+18= 27

18x+27= 477

now solve for x

-27 on both sides

18x= 450

÷18 on both sides

x= 25

3 0
3 years ago
Read 2 more answers
tmara is making a medium length necklace. write an expression that shows how nuch it will cost tamara for the chain,pendant,and
erastova [34]

Answer:

1/4(n), $7.50

Step-by-step explanation:

Expanded: cost = 0.25 * chains + 0.25 * pendants + 0.25 * beads

Simplified: c = (1/4)(total number of items)

Expression only: 1/4n where n = # chains + # pendants + # beads purchased

Total cost of 30 beads = 1/4(30) = 7.5 = $7.50

8 0
3 years ago
Qualification exams for becoming a state-certified welding inspector are based on multiple-choice tests. As in any multiple-choi
erik [133]

Answer:

(a) The probability distribution of the random variable <em>X</em> is Binomial.

(b) The mean and standard deviation of the 25-question test are 5 and 2 respectively.

(c) The value of <em>x</em> is 0.34.

Step-by-step explanation:

The random variable <em>X </em>is defined as the number of correct answers given by a person who is guessing each answer on a 25-question exam.

There are five possible answer for every question.

This implies that the probability of getting a correct answer is:

<em>P</em> (X) = 0.20.

There are a total of <em>n</em> = 25 questions.

Every answer is independent of the others.

(a)

The random variable <em>X</em> has  finite number of independent trials (i.e. 25 questions). There are only two outcomes for each trial, i.e. Success = correct answer and Failure = wrong answer. Each trial has the same probability of success (, i.e. P (X) = 0.25).

Thus, the probability distribution of the random variable <em>X</em> is Binomial with parameters <em>n</em> = 25 and <em>p</em> = 0.20.

(b)

Compute the mean of the random variable <em>X</em> as follows:

E(X)=np\\=25\times 0.20\\=5

Compute the standard deviation of the random variable <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}\\=\sqrt{25\times 0.20\times (1-0.20)}\\=2

Thus, the mean and standard deviation of the 25-question test are 5 and 2 respectively.

(c)

The sample is large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 5

2. n(1 - p) ≥ 5

Check the conditions as follows:

np=25\times 0.20=5=5\\\\n(1-p)=25\times (1-0.20)=20>5

Thus, a Normal approximation to binomial can be applied.

So,  X\sim N(5, 2^{2})

It is provided that the minimum passing score foe the test is such that only 1% of students who are guessing will pass the test.

That is P (X < x) = 0.01.

⇒ P (Z < z) = 0.01

The value of <em>z</em> is -2.33.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\-2.33=\frac{x-5}{2}\\\\x=5-(2.33\times 2)\\\\x=0.34

Thus, the value of <em>x</em> is 0.34.

4 0
4 years ago
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