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Ivanshal [37]
3 years ago
12

PLEASE HELP GUYS PLEASE!!!! I will LOVE WHOEVER HELP ME FOREVER

Chemistry
2 answers:
Umnica [9.8K]3 years ago
8 0

Answer:

d

Explanation:

ignition is a chemical. reaction

Vladimir79 [104]3 years ago
3 0

Answer:

B. It is highly flammable.

Explanation:

Chemical properties deal with how the substance will behave when brought into contact with other substances, and usually have to do with it undergoing some kind of reaction. Flammability is a chemical property.

Density, melting point, and color are all considered physical properties.

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What force is the type of intermolecular force that would be present between molecules of Cl2 ?
KatRina [158]

Cl2 is nonpolar so it has to be only London dispersion force (LDF)

7 0
3 years ago
Read 2 more answers
A 0.63 mole sample of CO2 is in a 750 mL container. What is the pressure of the gas in torr when the has is held at -35.6oC?
kipiarov [429]

Answer:

12426torr

Explanation:

The following data were obtained from the question:

n = 0.63 mole

V = 750mL = 750/1000 = 0.75L

T = -35.6°C = -35.6 + 273 = 237.4K

R =0.082atm.L/Kmol

P =?

Using the ideal gas equation PV = nRT, the pressure can be obtained as follows:

PV = nRT

P = nRT/V

P = (0.63 x 0.082 x 237.4)/0.75

P = 16.35atm

Now let us convert this pressure (i.e 16.35atm) to a pressure in torr. This is illustrated below:

1atm = 760torr

16.35atm = 16.35 x 760 = 12426torr

Therefore, the pressure of the gas is 12426torr

4 0
3 years ago
Read 2 more answers
The percentage yield of the following reaction is 85 %. 2 Al, +31--> 2 AICI. How many grams of AICI, will be actually obtaine
Readme [11.4K]

Answer:

Assuming the product is AlCl3

Assuming its 1008 g of metalic Al

It will yeld 4234 g of aluminium chloride.

Explanation:

Al molar mass is 26.98 g/mol, so in 1008 g of Al there is 37.36 mols of Al

The stoichometry ratio between Al and AlCl3 is 1:1, so 37.36 mols of Al would form 37.36 mols of AlCl3 if the reaction were complete, but only 85% yelds, so 1008 g of Al makes up to 0.85x37.36 mols of AlCl3 (31.76 moles)

AlCl3 molar mas is 133.33 g/mol, so 31.76 moles has 4234 g

6 0
3 years ago
The analysis of a compound containing K, P and O showed 55 % K, 15 % P and 30 % O, set up the simplest empirical formula of this
Leokris [45]

Answer:

Empirical formula is K₃PO₄.

Explanation:

Given data:

Percentage of K = 55%

Percentage of P = 15%

Percentage of O = 30%

Empirical formula = ?

Solution:

Number of gram atoms of K = 55 / 39.098 = 1.41

Number of gram atoms of P = 15 /30.974= 0.48

Number of gram atoms of O = 30 / 15.999 = 1.88

Atomic ratio:

             K                      :          P                   :         O

           1.41/0.48            :       0.48/0.48        :       1.88/0.48

               3                     :           1                    :            4

K : P : O = 3 : 1 : 4

Empirical formula is K₃PO₄.

4 0
3 years ago
Hey umm can yall help me
Bezzdna [24]

Answer:

C

Explanation:

Because a compound is TWO or MORE atoms combined together and in C there are two different atoms in answer choice C

8 0
3 years ago
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