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Mariulka [41]
2 years ago
13

If represents one atom of nitrogen, and represents one atom of oxygen, which picture represents 2NO2

Chemistry
2 answers:
storchak [24]2 years ago
7 0

Answer: D

Explanation:

Now go study ._.

Lostsunrise [7]2 years ago
4 0

Answer:

I do believe its D as well

Explanation:

and some people just dont have time like me lol.

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Cu2 -> Cu2+ is it getting oxidized?
KIM [24]

Answer:

Explanation:

Cu²⁺ + 2e⁻  →  Cu   ( copper gets reduced )

Cu  → Cu²⁺ + 2e⁻ (  copper gets oxidized )

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

7 0
3 years ago
What is the chemical formula of magnesium bromide?
Angelina_Jolie [31]

MgBr2 is the chemical formula for magnesium bromide

6 0
3 years ago
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A student performs an experiment similar to what you will be doing in lab, except using titanium metal instead of magnesium meta
Genrish500 [490]

Answer:

n = 0.0022 mol

Explanation:

Moles is denoted by given mass divided by the molar mass ,  

Hence ,  

n = w / m  

n = moles ,  

w = given mass ,  

m = molar mass .  

From the information of the question ,

w = 0.108 g

As we known ,

The molar mass of titanium = 47.867 g / mol

The mole of titanium can be caused by using the above relation , i.e. ,

n = w / m  

n = 0.108 g / 47.867 g / mol

n = 0.0022 mol

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3 years ago
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5 0
3 years ago
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Balance the equation and determine how many liter of nitrogen are required to react with 7.3 L of hydrogen to produce ammonia (n
Musya8 [376]

Answer:

4.867 L of ammonia

Explanation:

Using Haber's process to form ammonia using Nitrogen and hydrogen, the equation is :

N₂ + 3H₂ → 2NH₃

Here, 3 moles of hydrogen gas gives 2 moles of ammonia.

1 mole of any substance occupies 22.4L at STP

So, 3 x 22.4L of hydrogen gives 2 x 22.4 L of ammonia

Then 7.3 L of hydrogen will give:

=\frac{7.3 \times 2 \times22.4 }{3 \times22.4}

=\frac{7.3 \times 2}{3}

= 4.867 L of ammonia

3 0
3 years ago
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