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kompoz [17]
2 years ago
9

Find the value of d/с​

Mathematics
1 answer:
Hitman42 [59]2 years ago
6 0
Washington DC because it’s D/C and that’s the first thing that came to mind
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Two groups of bikers leave the same camp heading in different directions. Each group travels 4 miles, then changes direction and
devlian [24]

Group B is farther from camp.

7 0
2 years ago
What are the slope and y-intercept of the graph of this equation?
schepotkina [342]

Answer:

slope = y = 1/2

y-intercept = b = -3

Step-by-step explanation:

slope intercept equation:

y = mx + b----->(equation 1)

m is slope

b is y-intercept

y = 1/2x - 3----->(equation 2)

Compare (equation 1) and (equation 1)

slope = y = 1/2

y-intercept = b = -3

3 0
2 years ago
The American Water Works Association reports that the per capita water use in a single-family home is 74 gallons per day. Legacy
Lunna [17]

Answer:

Reject H0 since test statistic <-2.492

Step-by-step explanation:

Given that the American Water Works Association reports that the per capita water use in a single-family home is 74 gallons per day.

n = 25

x bar = 69

s= 8.3

std error = s/sqrt n = \frac{8.3}{5} \\=1.66

H0:\bar x = 74

Ha: \bar x

(Left tailed test at 5% significance level)

a) Reject H0 if t\leq-2.492

b) Test statistic = mean difference/std error

= \frac{69-74}{1.66} \\=-3.012\\

=-3.01

df =24

c) Reject H0

6 0
3 years ago
At an effective annual interest rate of i &gt; 0, each of the following two sets of payments has present value K: (i) A payment
IgorLugansk [536]

Answer:

The present value of K is, K=251.35

Step-by-step explanation:

Hi

First of all, we need to construct an equation system, so

(1)K=\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}

(2)K=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}

Then we equalize both of them so we can find i

(3)\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}

To solve it we can multiply (3)*(1+i)^{4} to obtain (1+i)^{4}*(\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}), then we have 225(1+i)^{2}+225=169(1+i)^{3}+169(1+i)^{2}.

This leads to a third-grade polynomial 169i^{3}+451i^{2}+395i-112=0, after computing this expression, we find only one real root i=0.2224.

Finally, we replace it in (1) or (2), let's do it in (1) K=\frac{169}{(1+0.2224)} +\frac{169}{(1+0.2224)^{2}}\\\\K=251.35

8 0
3 years ago
Please help me w this
scoundrel [369]

Answer:

54

Step-by-step explanation:

54

8 0
2 years ago
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