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professor190 [17]
3 years ago
13

HELP PLEASE ANYONE CAN ANSWER

Mathematics
1 answer:
ladessa [460]3 years ago
5 0

Answer:

∆SUY=90

∆XUT=90

7x+8x+90=180(being linear pair)

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Which table shows the same relationship as y = -x^2 + 3x?
kkurt [141]

Answer:

H

Step-by-step explanation:

given y = -x² + 3x.

let f(x) be y.

f(-2) = -(-2)² + 3(-2) = -10

f(-1) = -(-1)² + 3(-1) = -4

f(0) = -(0)² + 3(0) = 0

f(1) = -(1)² + 3(1) = 2

f(2) = -(2)² + 3(2) = 2

8 0
3 years ago
PLEASE PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!
Oksanka [162]

The answer is Option B (x + 6)(x^2 + 8)

Step-by-step explanation:

Step 1: Group the given cubic polynomial into two sections.  

So  polynomial can be  grouped as

(x^3 + 6x^2) + (8x + 48)

Step 2:Find what's the common in each section.

In section (x^3 + 6x^2)  the come term is x^2

In section (8x + 48)  the come term is 8

Step 3:Factor the commonalities out of the two terms.

Factoring out x^2 from the first section  (x^3 + 6x^2), we get  x^2(x + 6)

Factoring out 8 from the second section(8x + 48) ,  we will get 8(x + 6).

Step 4: Combine the factors together for terms contains the same factor,

Combining we get,\left(x+6\right)\left(x^2+8\right)

\left(x+6\right)\left(x^2+8\right)

7 0
3 years ago
Lexi needs 144 beads.A large box holds 100 beads.A medium box holds 10 beads.a small box holds 1 bead.lexi already had 1 large b
saveliy_v [14]

The total number of beads that Lexi could accommodate based on the on hand items is 101 beads. Subtract the number of beads she needs which is 144 beads with 101 beads. The amount of beads that would need a box is 43 beads. Since a medium box could only accommodate 10 beads at a time, divide 43 with 10 and the answer would be 4 remainder 3. Thus Lexi would only need 4 medium boxes. 

3 0
3 years ago
after two tests carol has a total score of 170. the score on her first test was 8 points higher than the score on her second tes
RoseWind [281]
X stands for the score of her first test
Y stands for the score of her second test

7 0
3 years ago
Find the number of all 20 digit integers in which no two consecutive digits are the same
Arturiano [62]
For the first digit of the required 20-digit number, we can have 9 choices for the number, those are the digits 1 to 9. In the second digit of the number, we will only have 8 choices. That is because, we don't want to write a number in the second digit that is similar to the first digit and the third digit.

Similarly, in the third digit's place, we will only have 8 choices because we do not want the digit to be similar to the second digit and the fourth digit. This will go on up until the 19th digit. In the 20th digit, we will also have 9 choices (from 0-9) but we do not want the digit to be similar to the 19th digit. 

From the explanation given above, we have the number of ways,

    n = 9 x 8^(19 - 1) x 9  = 1.459 x 10^18

<em>ANSWER: 1.459 x 10^18</em>
5 0
4 years ago
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