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aliina [53]
3 years ago
10

Molecules have Question 16 options: A) neither kinetic nor potential energy. B) only potential energy. C) only kinetic energy. D

) both potential and kinetic energy.
Chemistry
1 answer:
viktelen [127]3 years ago
8 0

Answer:

both potential and kinetic energy

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A 21.496 grams sample of magnesium is burned in air to form magnesium oxide and magnesium nitride. When the products are treated
Bond [772]

25.898 g is the amount of magnesium nitride and magnesium oxide formed.

Step1 2Mg(s)+ O2(g)-----> 2 MgO(s)

3Mg(s)+N2(g)------> Mg3N2(s)

Mg3N2(s)+ 6 H2O(l)---> 3Mg(OH)2 + 2 NH3(g)

Step2 Moles of NH3 = (2.813/17)

Moles of Mg3N2= (1/2) Moles of NH3 = (2.813/2x17)= 2.813/34

Mass of Mg3N2 = (2.813/34) x100 =8.274g (Molar mass of Mg3N2=100)

Step3 Mass of Mg in Mg3N2 =(72/100) x8.274 =5.957g

Mass of Mg converted in MgO= 21.496-5.957=15.539

Moles of MgO= Moles of Mg = 15.539/24

Mass of MgO = 15.539x40/24 =25.898 g.

Magnesium is a cofactor for over 300 enzymatic systems that regulate various biochemical reactions in the body, including protein synthesis, muscle and nerve function, glycemic control, and blood pressure regulation [1-3].

Learn more about magnesium at

brainly.com/question/5759562

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8 0
1 year ago
How many Mn atoms are found in the following compound?<br> 3Cr(MnO4)6
lina2011 [118]

poopyAnswer:

Explanation:

pooopy

5 0
3 years ago
Explain the function of the valence ring?
kirill115 [55]

Answer:

It provides the electrons that "make" electricity and it contains the electrons that are involved in molecular bond formation.

7 0
3 years ago
The decomposition of potassium chlorate into kcl &amp; o2 is used as a source of oxygen in the laboratory. How many moles of pot
fredd [130]

Answer:

10moles of kcl

Explanation:

2 K C l O3 →  2 K C l  +  3 O 2

Notice that you have a  2 : 3  mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you'll always produce 2/3 times more moles of the latter.

15 mol of O2 * ((2mol of KCLO3)/(3mol of O2))= 15*2/3=10 Mol

5 0
4 years ago
Calculate the empirical formula of a compound that is 42.9% Carbon and 57.1% Oxygen.
Marrrta [24]

Answer:

CO.

Explanation:

Assuming the given percentages are by mass, we can solve this problem via imagining we have <em>100 g of the compound</em>, if that were the case we would have:

  • 42.9 g of C
  • 57.1 g of O

Now we <u>convert those masses into moles</u>, using the<em> elements' respective molar masses</em>:

  • 42.9 g of C ÷ 12 g/mol =  3.57 mol C
  • 57.1 g of O ÷ 16 g/mol =  3.58 mol O

As the number of C moles and O moles is roughly the same, the empirical formula for the compound is <em>CO</em>.

4 0
3 years ago
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