Answer:
a) 8×10²³ molecules of N2
Explanation:
Let us consider the same temperature and pressure of both sample are standard temperature and pressure.
Standard temperature = 273.15 K
Standard pressure = 1 atm
Number of moles of CO₂ = 0.107 mol
Volume of CO₂ = ?
Solution:
PV = nRT
R = general gas constant = 0.0821 atm.L /mol.K
1 atm × V = 0.107 mol × 0.0821 atm.L /mol.K × 273.15 K
1 atm × V = 2.4 atm.L
V = 2.4 atm.L/1 atm
V = 2.4 L
Volume of N₂:
Number of moles of N₂:
1 mole = 6.022 ×10²³ molecules
8×10²³ molecules × 1 mol / 6.022 ×10²³ molecules
1.33 mol
PV = nRT
R = general gas constant = 0.0821 atm.L /mol.K
1 atm × V = 1.33 mol × 0.0821 atm.L /mol.K × 273.15 K
1 atm × V = 29.83 atm.L
V = 29.83 atm.L/1 atm
V = 29.83 L
Concentration is volume over number of moles
False - A producer always provides food for the consumer.
The bathtub of water would melt the most ice because it has a larger area
