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Serggg [28]
3 years ago
5

Molecular geometry of NCI 4 +

Chemistry
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

blah blah blah blah i need the points

Explanation:

sorry bro

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Calculate the osmotic pressure of a magnesium citrate laxative solution containing 25.5 g of magnesium citrate in 244 mL of solu
Vera_Pavlovna [14]

Answer:

The answer to your question is π = 12.47 atm

Explanation:

Data

mass of Magnesium citrate = 25.5 g

volume of solution = 244 ml

temperature = 37°C

molar mass C₆H₆MgO₇ = (12 x 6) + (1 x 6) + (24 x 1) + (16 x 7) = 214 g

Osmotic pressure = π = ?

Process

1.- Calculate the moles of magnesium citrate

                         214 grams ----------------- 1 mol

                          25.5 grams ---------------  x

                           x = (25.5 x 1)/214

                           x = 0.119

2.- Calculate molarity

Molarity = moles/volume

Molarity = 0.119/0.244

Molarity = 0.49

3.- Calculate osmotic pressure

π = MRT

π = (0.49)(0.0821)(37 + 273)

π = (0.49)(0.0821)(310)

π = 12.47 atm

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3 years ago
Use the choose reaction drop down menu to see other equations, and balance them. Check your answers and then write the balanced
d1i1m1o1n [39]
3 and then you do that yea
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What are essential elements in plants?​
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Chlorophyll is one. I can't quite remember other

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If a 22.4 L volume of a sample of gas has a density of 0.900 grams/L at 1.00 atm and 0.00°C. Given
disa [49]

Answer:

Formula Weight of gas sample = 20.1 g/mole => Neon (Ne)

Explanation:

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R = 0.08206 L·atm/mole·K

T = 0.00°C = 273Kfwt = (0.900g/L)(0.08206L·atm/mole·K )(273K)

= 20.1 g/mol => Neon (Ne)

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snow_lady [41]

Answer:

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Explanation:

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