Molecular geometry of NCI 4 +

Chemistry

1 answer:

tatuchka [14]3 years ago

5 0

Answer:

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Explanation:

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Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.

BaLLatris [955]

Answer:

59.8%

Explanation:

First find the Mr of manganese (III) nitrate.

Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = 240.9

Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:

Mr of (O₃)₃ = (16 × 3) × 3 = 144

Now we can find percentage composition / percentage by mass of oxygen.

% composition = $\frac{Mr\ of\ oxygen\ in\ compound}{Mr\ of\ compound}$ × 100

% composition = $\frac{144}{240.9}$ × 100 = 59.776%

∴ % compostion of oxygen in maganese(III)nitrate is 59.8% (to 3 significant figures).

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2 years ago

How many cubic centimeters are there in 200 milliliters?

DiKsa [7]

Answer:

200 mL = 200 cm³

Explanation:

The relationship between cm³ and mL is 1:1.

1 cm³ = 1 mL

Thus, 200 mL is converted to cm³ as follows:

(200 mL)(1 cm³/1 mL) = 200 cm³

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3 years ago

URGENT!!!!!!!!Which reaction takes place in a nuclear fission reactor?

ivolga24 [154]

Answer: The correct answer is Option d.

Explanation:

Nuclear fission reaction is defined as the reaction in which 1 heavier nuclei splits into two or more smaller nuclei.

As, nuclear fission reactors require a large amount of energy to split the nucleus, hence it is bombarded with a particle in order to star the reaction.

In a nuclear reaction, a large fissile atomic nucleus like Uranium-235 $(_{92}^{235}\textrm{U})$ or Plutonium-239 $(_{94}^{239}\textrm{Pu})$ when absorbs a neutron, it undergoes nuclear fission reaction.