3 years ago

Check my answer?

Mathematics

2 answers:

kirza4 [7]3 years ago

7 0

Answers for this test, unit 3 lesson one are
1a 2a 3b 4d 5b

sergij07 [2.7K]3 years ago

5 0

I think you have it upside down.
When you solve a proportion, you cross multiply. You can have the same proportion just by interchanging 8 and b

a/8 = b / 15 When you cross multiply, you get
15a = 8b Try the given proportion to see what happens

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Can someone help with this math problem? 3 (x+6) = 27

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Answer:

x = 3

Step-by-step explanation:

Use distributive property: a(b +c) =(a*b) + (a*c)

3(x + 6) = 27

3*x + 3*6 = 27

3x + 18 = 27 {Subtract 18 from both sides}

3x + 18 -18 = 27 - 18

3x = 9 {Divide both sides by 3}

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Click once to choose an answer. Click again to change your answer. Choose all that locate the ordered pair in the correct quadra

forsale [732]

Answer:

$Quadrant\ IV = (5, -3)$

$Quadrant\ I = (9, 11)$

$Quadrant\ II = (-1, 3)$

$Quadrant\ III = (-2, -4)$

Step-by-step explanation:

Given

$Quadrant\ IV = (5, -3)$

$Quadrant\ II = (-4, -8)$

$Quadrant\ I = (9, 11)$

$Quadrant\ II = (-1, 3)$

$Quadrant\ III = (-2, -4)$

Required

Determine which coordinate fall in the right quadrant

First, we split the each quadrant into x and y axis

In the first:

x and y is +

In the second:

x is - and y is +

In the third

x and y are -

In the fourth

x is + and y is -

Comparing the given coordinates to their respective quadrants, base on the conditions stated above

$Quadrant\ IV = (5, -3)$ is correct

$Quadrant\ I = (9, 11)$ is correct

$Quadrant\ II = (-1, 3)$ is correct

$Quadrant\ III = (-2, -4)$ is correct

$Quadrant\ II = (-4, -8)$ is incorrect

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3 years ago