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pishuonlain [190]
3 years ago
6

In the equation (m^5/6) (m^1/6)^7 = m^x , what is the value of x that makes the equation true?

Mathematics
1 answer:
vlabodo [156]3 years ago
6 0

{m}^{ \frac{5}{6} }  \times (m {}^{ \frac{1}{6} } ) {}^{7 }  = m {}^{x}

m {}^{ \frac{5}{6} }  \times m {}^{ \frac{7}{6} }  = m {}^{x}

{m}^{ \frac{5 \times 7}{6 \times 6} }  =  {m}^{x}

\frac{35}{36}  = x

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frutty [35]

Answer: 0.8015

Step-by-step explanation:

Let F= event that a person has flu

H= event that person has a high temperature.

As per given,

P(F) =0.35

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By Bayes theorem, we have

P(F|H)=\dfrac{P(F)\timesP(H|F)}{P(F)\timesP(H|F)+P(F')\timesP(H|F')}\\\\=\dfrac{0.35\times0.90}{0.35\times0.90+0.65\times0.12}\\\\=\dfrac{0.315}{0.315+0.078}\approx0.8015

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3 years ago
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Answer:

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Flipping a coin and rolling a number cube are both independent events. Independent events do not rely on the outcome of any previous events.  This means that whatever you flip on the coin will have no effect on whatever you roll on the number cube and each flip of the coin or roll of the cube has the same probability as the flip or roll before.  

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\frac{1}{2}*\frac{1}{3}=\frac{1}{6}

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Check the picture below.

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Answer:

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