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pishuonlain [190]
2 years ago
6

In the equation (m^5/6) (m^1/6)^7 = m^x , what is the value of x that makes the equation true?

Mathematics
1 answer:
vlabodo [156]2 years ago
6 0

{m}^{ \frac{5}{6} }  \times (m {}^{ \frac{1}{6} } ) {}^{7 }  = m {}^{x}

m {}^{ \frac{5}{6} }  \times m {}^{ \frac{7}{6} }  = m {}^{x}

{m}^{ \frac{5 \times 7}{6 \times 6} }  =  {m}^{x}

\frac{35}{36}  = x

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line AB has endpoints A (-3, 1) and B (4, 5), find the coordinates of point p on directed line segment AB that partitions AB in
Margarita [4]
<h3>Given</h3>

A(-3, 1), B(4, 5)

<h3>Find</h3>

coordinates of P on AB such that AP/PB = 5/2

<h3>Solution</h3>

AP/PB = 5/2 . . . . . desired result

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How many groups of 3/4 are in each of the following quantities?
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Answer:

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Step-by-step explanation:

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3 years ago
On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

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c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

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Thus 18 pies and 22 cakes were sold

3 0
3 years ago
If y varies directly with x, find the value of y when x = 27 for the direct variation with the given information. y = 7 when x =
ElenaW [278]

Given:

y varies directly with x,

It is given that y = 7 when x = -9.

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The value of y when x = 27 for the direct variation.

Solution:

It is given that y varies directly with x, so

y\propto x

y=kx             ...(i)

Where, k is the constant of proportionality.

It is given that y = 7 when x = -9. Putting these values in (i), we get

7=k(-9)

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y=-\dfrac{7}{9}x

Putting x=27,  we get

y=-\dfrac{7}{9}(27)

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Therefore, the required value is y=-21.

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2 years ago
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