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Studentka2010 [4]
3 years ago
8

a dime is dropped from a building at 1.024 ft . if the equation for height as a function of time is h(t)=-16t^2+ initial height

where is t is time in seconds and h(t) is height in feet, how many seconds will it take for the dime to hit the ground?
Mathematics
1 answer:
babunello [35]3 years ago
7 0

Answer:

The dime hits the ground after 8 sec.

Step-by-step explanation:

Set h(t) = -16t^2 + h(0) equal to 0:  -16t^2 + 1,024 ft = 0, or:

16t^2 = 1,024 ft, or:

 t^2 =  64 ft^2

Then t = +8 sec

The dime hits the ground after 8 sec.

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Step 1:

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a)

\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{  }\times\text{  300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72  students} \end{gathered}

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