Answer:
<u>167.2 g</u>
Explanation:
Known
VC4H10 = 21.3
T = 0.00 C (convert to Kelvin: 273 K)
P = 1.00 atm
Unknown
m = ?g
1. <u>Write the balanced chemical equation</u>
1 C4H10 + 1O2 -----> 4 CO2 + 5 H2O
2. <u>Find the volume ratio of Carbon Dioxide to Butane </u>
1 C4H10 4 CO2 = 4 volumes CO2 / 1 volume C4H10
3.<u> Multiply by the known volume of n (butane)</u>
21.3 L C4H10 x 4 volumes CO2 / 1 volume C4H10 = 85.2 L C4H10
4. <u>Use ideal gas law</u>
PV = nRT solve for n ----> n = PV/RT
n= (1.00 atm) (85.2 L) / (0.0821 L atm/mol K) (273) = 3.80 mol CO2
5.<u> Find molar mass of CO2</u>
1 C x 12 + 2 O x 16 = 44.00
6. <u>Multiply the ideal gas law solution (3.80) by molar mass CO2 (44.00)</u>
3.80 mol CO2 x 44.00 g CO2
= 167.2 g CO2
<span>Like dissolves like and unlike repels like. This applies to the polarity of the solutions. Polar dissolves polar and non-polar does not mix with polar solutions. In this case, the polar substance that can mix with water. Sugar and salt can be dissolved through agitation. Oil which is nonpolar is immiscible in water. Hence answer is D. </span>
Answer:
See explaination
Explanation:
1) Pb(NO3)2 => Pb2+ + 2 NO3-
[Pb2+] = [Pb(NO3)2] = 7.56 mM = 7.56 x 10-3 M
Pb(IO3)2 <=> Pb2+ + 2 IO3-
Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13
7.56 x 10-3 x [IO3-]2 = 2.5 x 10-13
[IO3-] = 5.75 x 10-6 M ≈ 5.8 x 10-6 M
(2) [Pb2+] = 1.7 x 10-6 M
Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13
1.7 x 10-6 x [IO3-]2 = 2.5 x 10-13
[IO3-] = 3.83 x 10-4 M
[IO3-]from Pb(IO3)2 = 2 x [Pb2+]
= 2 x 1.7 x 10-6 = 3.4 x 10-6 M
[IO3-]from NaIO3 = [IO3-] - [IO3-]from Pb(IO3)2
= 3.83 x 10-4 - 3.4 x 10-6
= 3.80 x 10-4 M
NaIO3 => Na+ + IO3-
[NaIO3] = [IO3-]from NaIO3
= 3.80 x 10-4 M ≈ 3.8 x 10-4 M
Answer:
An animal will eat the grass and the energy then gets passed through the food chain
Explanation:
