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gogolik [260]
3 years ago
7

True/False: RNA contains uracil instead of thymine. a. True b. False

Biology
2 answers:
sergey [27]3 years ago
5 0
The answer would be A. True
gtnhenbr [62]3 years ago
3 0

Answer:

True

Explanation:

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How many mongo seed are equal to 3.50 moles of mongo seeds?​
frozen [14]

Answer:

The correct answer is - 2.107 x 10^24 mango seeds.

Explanation:

Given:-

number of moles of mango seeds = 3.50 mol

Solution:-

1 mol of mango seeds = 6.02 x 10^23 mango seeds

6.02 x 10^23 is Avagadro numbers

1 mole is the number of particles contained in a substance . The number of moles can also be calculated by dividing the mass by the molar mass of the element or molecule of the substance  with the Avogadro's number.

Therefore,

3.50 mol of mango seeds = 3.50 x 6.02 x 10^23 mango seeds

3.50 mol of mango seeds = 21.07 x 10^23 mango seeds

3.50 mol of mango seeds = 2.107 x 10^24 mango seeds

3 0
3 years ago
In pea plants, tallness (T) is dominant to shortness (t). What is the predicted genotypic ratio of the offspring if a homozygous
tino4ka555 [31]
First, to answer this question, you need to draw a Punnett square. So you put the homozygous short alleles (tt) on top of the square, and the heterozygous tall alleles (Tt) on the left side of the square (or vice versa, it doesn't really matter).

When you create the Punnett Square, you then perform the cross between the two plants' alleles. I cross t with T and that gives me Tt. Same with the next one, t and T becomes Tt. Then, I cross t with t and that gives me tt. Same with the next one, t and t becomes tt.

So, the answer here would then be c. 50 percent Tt, 50 percent tt. You might say, well, couldn't answer d also work? Answer d could only work if the question was asking for the phenotypic ratio of the offspring. Then you could say 50% tall, 50% short. But the question asks for the genotypic ratio, so it would instead be c. 50 percent Tt, 50 percent tt.

Hope this helps! 
7 0
4 years ago
Read 2 more answers
Seaweed cover increased the most when both urchins and limpets were removed. How might you explain this result?
weqwewe [10]

Only urchins were removed, which resulted in an increase in limpet population and decrease in seaweed cover.

  • Sea urchins and limpets both consume seaweed, making them competitors for it. The limpet population grows as a result of the urchin removal, having a greater impact on the amount of seaweed present.
  • The biodiversity of these settings can be wiped out if seaweed builds up in bodies of water. This issue arises when there is an overabundance of algae, which, in search of additional food, proliferate aggressively and cause pollution.
  • Additionally, life might end where there is pollution. Hedgehogs and limpets can play a significant role in this situation because they feed on seaweed, which helps to control the problem of its excessive profusion.
  • A lot of research has been done to determine the value of these two species in preventing pollution brought on by the growth of seaweed.
  • When the sea urchins and limpets were removed in the study mentioned in the question above, seaweed cover rose significantly more than when only the sea urchins were removed.
  • This most likely occurred because the limpet population expanded and the amount of seaweed was reduced when only the hedgehogs were eliminated.

Learn more about the Seaweed with the help of the given link:

brainly.com/question/10244123

#SPJ4

4 0
1 year ago
Lactic acid fermentation occurs in
Studentka2010 [4]

I think it's muscle cells cuz it's anaerobic respiration and It cannot be in plants or food sources

hope this helps ;)

6 0
3 years ago
HELPPP HELPPP !!!
kompoz [17]
It engages in a reforestation project
5 0
4 years ago
Read 2 more answers
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