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Mathematics

1 answer:

Leni [432]3 years ago

8 0

The formula for direct variation is y = kx where k ≠ 0

y = 9/x is an inverse relation

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(2.5×10^−10)(7×10^−6)

Nataly [62]

(2.5×10^−10)(7×10^−6)
= (2.5 x 7) (10^−10 x 10^−6)
= 17.5 x 10^-16
= 1.75 x 10^-15

answer
B. 1.75×10^−15

6 0

3 years ago

PIUWawilities

blondinia [14]

Answer:

23.44%

Step-by-step explanation:

The probability of getting a 4 on the first 2 throws and different numbers on the last 5 throws = 1/6 * 1/6 * (5/6)^5

= 0.01116

There are 7C2 ways of the 2 4's being in different positions

= 7*6 / 2 = 21 ways.

So the required probability = 0.01116 * 21

= 0.2344 or 23.44%.

3 0

3 years ago

Factor completely. <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra

Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

$x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)$

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize $x^2-\frac13$ as yet another difference of squares: