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Juli2301 [7.4K]
3 years ago
11

*10 points* ANSWER ASAP WILL MARK AS BRAINLIEST!!

Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0

Answer:

1) yes

2)yes

3) yes

4) no

Step-by-step explanation:

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The end points of Line GH are G (10,2) and H(4,8). Find the coordinates of the midpoint M.
nikitadnepr [17]

Answer:

(10-4)/2 , (2-8)/2

6/2 , -6/2

Midpoint = (3,-3)

7 0
2 years ago
(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

7 0
3 years ago
If the original quantity is 10 and the new quantity is 6, what is percent increase
Ad libitum [116K]

Answer:

Using the percentage difference formula you can find the percentage decrease.

SO its

100(new-old/new)

So we solve

10-6=4

4/10= 2/5

2/5*100=200/5

40

40 percent decrease

3 0
3 years ago
The graph of the function above is shown below. Which of the following statements about f(x) is true? A. The function f(x) does
Sedbober [7]

Answer:

The correct answer is b)

Step-by-step explanation:

6 0
2 years ago
If 90 is 80 percent of the value what is the value
OLga [1]
If 90 is 80% of the whole value, then 1/4 of 90 added to 90 will be the value, because 1/4 of 80% (which is 20%) added to 80% will give us 100%

So,
90/4=12.5
90 + 12.5=102.5

At least, that's my take on it
5 0
3 years ago
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