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Wewaii [24]
3 years ago
9

The Least Squares Assumptions ​, where 1. The error term has conditional mean zero given ​: ​; 2. ​, are independent and identic

ally distributed​ (i.i.d.) draws from their joint​ distribution; and 3. Large outliers are​ unlikely: and have nonzero finite fourth moments. Suppose the first assumption is replaced with . What happens to ​? A. The slope changes to . B. The intercept changes to . C. Nothing changes. D. Both the intercept and the slope change to and respectively. Are the rest of the OLS assumptions​ satisfied? A. OLS assumption​ (3) is satisfied but not​ (2). B. Both OLS assumptions​ (2) and​ (3) are satisfied. C. OLS assumption​ (2) is satisfied but not​ (3). D. Neither OLS assumption​ (2) nor​ (3) is satisfied.
Mathematics
1 answer:
Makovka662 [10]3 years ago
3 0

Step-by-step explanation:

is satisfied but not (3). D. Neither OLS assumption (2) nor (3) is satisfied.

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Step-by-step explanation:

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Last year, Jina opened an investment account with $8200. At the end of the year, the amount in the account had decreased by 6.5%
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Step-by-step explanation:

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Effectus [21]

- 24 - 16x(  - 1) \\ 6 { }^{2}  \div 9

negative 24 minus 16x (-1) divided by 6^2 divided by 9

ANSWER

four divided by 81 and than X minus 24

4 \div 81x - 24
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Use Midpoint and Slope Formulas to complete the tables below.1. Find the midpoint of RP, given the coordinates R (5, 8) and P (3
poizon [28]

The midpoint formula for a segment is:

x_m,y_{_m}=\frac{(x_1+x_2)}{2},\frac{(y_1+y_2)}{2}

apply to points R and P

\begin{gathered} x_m,y_m=\frac{(5+3)}{2},\frac{(8+6)}{2} \\ x_m,y_m=\frac{8}{2},\frac{14}{2} \\ x_m,y_m=(4,7) \end{gathered}

using the definition of slope find the slope of the segment

m=\frac{y_2-y_1}{x_2-x_1}

apply to points R and P

\begin{gathered} m=\frac{8-6}{5-3} \\ m=\frac{2}{2} \\ m=1 \end{gathered}

to lines are parallel when the slopes are the same

\mleft\Vert m=1\mright?

two lines are perpendicular when the product of the slopes is equal to -1

\begin{gathered} m\cdot\perp m=-1 \\ 1\cdot\perp m=-1 \\ \perp m=-\frac{1}{1} \\ \perp m=-1 \end{gathered}

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1 year ago
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