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Ksju [112]
3 years ago
15

What is 904.358 rounded to the nearest ten and nearest tenth?

Mathematics
2 answers:
Oksana_A [137]3 years ago
6 0

the answer is 904.4

dsp733 years ago
3 0
904.348 rounded to the nearest ten is 900
904.358 rounded to the nearest tenth is 904.4
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Translate the phrase to an algebraic expression.
mario62 [17]

Answer:

A

Step-by-step explanation:

If it’s 80 less than, your subtracting and then 4 times a number is 4x so your answer is 4x-80

8 0
3 years ago
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6 divided by 2 (1+2)
user100 [1]
Observe. 

6/2(1+2)
6/2(3)
6/6
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4 years ago
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Find the area. Please help
Nutka1998 [239]

The answer to your question is 77 because the formula for area for a triangle is A=1/2BH and the base is 11 feet and the height is 14 feet. So, (14•11)/2 is 77. Therefore, 77 squared feet is the answer.

6 0
3 years ago
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
Each bag of apples weighs 4 1/2 lb how much do 6 bags weigh?
Serjik [45]

Answer:

The bags would weigh 27lbs. multiply 4 1/2 and6 and you get 27lbs.

4 0
4 years ago
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