Answer:
the rate of heat loss is 2.037152 W
Explanation:
Given data
stainless steel K = 16 W 
diameter (d1) = 10 cm
so radius (r1) = 10 /2 = 5 cm = 5 × 
radius (r2) = 0.2 + 5 = 5.2 cm = 5.2 ×
temperature = 25°C
surface heat transfer coefficient = 6 6 W 
outside air temperature = 15°C
To find out
the rate of heat loss
Solution
we know current is pass in series from temperature = 25°C to 15°C
first pass through through resistance R1 i.e.
R1 = ( r2 - r1 ) / 4
× r1 × r2 × K
R1 = ( 5.2 - 5 ) / 4 × 5 × 5.2 × 16 × 
R1 = 3.825 × 
same like we calculate for resistance R2 we know i.e.
R2 = 1 / ( h × area )
here area = 4 r2²
area = 4 (5.2 × )² = 0.033979
so R2 = 1 / ( h × area ) = 1 / ( 6 × 0.033979 )
R2 = 4.90499
now we calculate the heat flex rate by the initial and final temp and R1 and R2
i.e.
heat loss = T1 -T2 / R1 + R2
heat loss = 25 -15 / 3.825 × + 4.90499
heat loss = 2.037152 W
Technician A says that relays can fail because the relay winding is open. Technician A is correct.
<h3>What is winding?</h3>
A single turn of the wound material, which is material wrapped or coiled around an object.
Poor contact alignment and open coils can also cause relays to malfunction.
The most important aspect impacting relay dependability is choosing the right relay type for a particular application. When incorporating them into circuits, several subpar design techniques are employed.
Hence, technician A is correct.
To learn more about the winding refer;
brainly.com/question/23369600
#SPJ1
Answer:
4.modifying a building to achieve an entirely new purpose
Answer:
At the time of the summer or winter solstices, the Sun is 23.44° degrees above or below the horizon, respectively, irrespective of time of day.
Explanation:
