1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
belka [17]
3 years ago
9

1/16 in. Converted to mm

Mathematics
2 answers:
Shalnov [3]3 years ago
7 0
1/16 converted into mm is 1.5875 mm
yKpoI14uk [10]3 years ago
7 0
The answer to your question is .0625
You might be interested in
No solution, one solution, ims y=x+4 y=x+7
Phantasy [73]

Answer:

no solution

Step-by-step explanation:

4 0
3 years ago
Help your girl out!!!!!!
yawa3891 [41]

All the details are in the attached picture; make a design according Your local requirements.

8 0
2 years ago
Read 2 more answers
Italic <br><br> Help I need help this is a question I don’t understand
aksik [14]

Answer:

Triangle ADB is an isosceles triangle that has been split in half. Isosceles triangles are triangles whose base angles are equal and has 2 equal side lengths. For example triangle ADB has AD and DB equal along with m<a and m<b equal

Therefore, if we split this triangle into two half's then they are congruent (the same)

Right triangles have a 90° angle, usually marked by a square

this means that m<DCA is 90°;AD=DB=14m; CB=AC=11; AB=AC+CB=22

Step-by-step explanation:

8 0
3 years ago
Which equation is not true for the solution x = -8
timama [110]
-3 1/4 ≠ 1/3x-2 3/4 

Explanation: I tried all the other answers and the results match the expression, however, when I plug in -8 into this equation, the results are not equivalent.
4 0
4 years ago
Question 6 Unsaved
Andreyy89

Question (6)

To answer this question we will find out both probabilities one by one and then we will multiply both probabilities.

Probability of getting a number card from standard deck will be

\frac{9\cdot 4}{52}=\frac{36}{52}

Probability of getting one ace will be \frac{4}{51} as we are given that second card is drawn without replacement.

To find the probability of choosing a number card and then an ace without replacement will be,

=\frac{4}{51}\cdot \frac{36}{52}=\frac{36}{13\cdot 51}\\&#10;\\&#10;=\frac{12}{13\cdot 17}=\frac{12}{221}

Therefore, first option is the correct choice.

Question (7)

Let us find out probability  that Shironda will get an even number after rolling a cube. We know that a standard dice contains 3 even and 3 odd numbers.

Probability of getting an even number = \frac{3}{6}=\frac{1}{2}.

Now let us find out probability of getting a black card from the deck.

Probability of getting a black card,

=\frac{2\cdot 13}{52}=\frac{26}{52}=\frac{1}{2}

Now we can get probability of getting  an even number and a black card by multiplying both probabilities.

\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}

Therefore, probability of getting an even number and a black card is 1/4.




8 0
4 years ago
Other questions:
  • Han, his sister, his dad, and his grandmother step onto a crowded bus with only 3 open seats for a 42-minute ride. They decide H
    8·2 answers
  • During a math game, a team kept track of their answers. The following diagram describes the number of answers they got right to
    7·2 answers
  • Solve for x, show all of your work: -2x – 6 &lt; 12
    10·2 answers
  • The infant mortality rate is defined as the number of infant deaths per 1,000 live births. This rate is often used as an indicato
    12·1 answer
  • Plzzzzz help <br><br><br> for brainliest<br> real answer or no brainliest
    7·1 answer
  • you only have to answer one, dont answer one thats been answered. also english please im a baby who wont learn new languages.
    12·2 answers
  • Describe how the graph of y = 2x is the same and different from the graph y = 2x - 7 .
    14·1 answer
  • Solve each inequality. <br> 1. 5x + 2 &lt;17
    6·1 answer
  • Which statement correctly maps AB to A′B′
    11·1 answer
  • HELP PLEASE
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!