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3 years ago

1 2/3 −3/4= _ −_= Rewrite using twelfths.

Mathematics

1 answer:

Triss [41]3 years ago

3 0

See the explanation I made for you!
Have a nice day!

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Candy is paving a narrow pathway with pebbles. She needs 100 pebbles for each four feet of path. How many feet can she pave if s

Nuetrik [128]

21 feet
525/100=5.25
5.25 times 4 = 21

6 0

3 years ago

9x²-6xy+4y²≥0 помогите

Liono4ka [1.6K]

I'm not very sure, but I hope it'll help.

8 0

4 years ago

Every digits + 798 is greater than any digit in 4325 explain why 4325 is greater than 798

maks197457 [2]

<span>It's because there are 4 numbers in 4325, and only 3 in 798.

Hope I Helped You!!! :-)

Have A Good Day!!!</span>

8 0

3 years ago

can someone help me please the problems are above i think or below whatever way they show up for people who help me

Phoenix [80]

Answer

a. The volume is multiplied by 4

b. The volume is doubled

Explanation

a. The volume of a cone with radius r and height h is $\pi r^2 h/3$ . If the radius is doubled, the new volume will be $\pi (2r)^2h/3$ , which is equal to $4\pi r^2h/3$ . This means that the volume is multiplied by 4.

b. The volume of a cone with radius r and height h is $\pi r^2 h/3$ . If the height is doubled, the new volume will be $\pi r^2(2h)/3$ , which is equal to $2\pi r^2 h/3$ . This means that the volume is multiplied by 2.

3 0

3 years ago

Find the limit............

liubo4ka [24]

Answer: $-\frac{9}{x^2}$

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Work Shown:

$\displaystyle \lim_{\Delta x \to 0^{+}} \frac{\frac{9}{x+\Delta x} - \frac{9}{x}}{\Delta x}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{\frac{9x}{x(x+\Delta x)} - \frac{9(x+\Delta x)}{x(x+\Delta x)}}{\Delta x}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{\frac{9x-9(x+\Delta x)}{x(x+\Delta x)}}{\Delta x}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{9x-9x-9\Delta x}{x\Delta x(x+\Delta x)}\\\\\\$

$\displaystyle \lim_{\Delta x \to 0^{+}} \frac{-9\Delta x}{x\Delta x(x+\Delta x)}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{-9}{x(x+\Delta x)}\\\\\\\displaystyle \frac{-9}{x(x+0)}\\\\\\\displaystyle -\frac{9}{x^2}\\\\\\$

The trick here is to first simplify the expression so that the $\Delta x$ term in the very lower denominator cancels out. This is to avoid dividing by zero. Once this division by zero error is avoided, we can replace the delta x term with 0 and evaluate the limit as $\Delta x$ approaches 0 from the right or positive direction.

5 0

3 years ago