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solniwko [45]
3 years ago
8

When planning your oral presentation, what can you do to prepare for the presentation? A) practice reading your presentation fro

m an index card. B) practice your presentation with your eyes closed. C) practice your presentation in front of friends or family. D) practice speaking clearly and directly to an audience of friends
Chemistry
2 answers:
nikklg [1K]3 years ago
6 0
I believe d is the best answer

ira [324]3 years ago
3 0

Answer:

The correct answer is D

Explanation:

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((2.0265-2.02)/2.0265) x 100.00
lianna [129]

Answer 0.5

when reporting calculations from sig figs, report the number of sig figs in the least accurate measurement

so

((2.0265-2.02)/2.0265) x 100.00

((2.0265/2.0265) - (2.02/2.03)) X 100.00

(1.0000 -0.995) X 100.00

0.005 X 100.00

0.5

3 0
3 years ago
Guys if you help me and I got a right I will Mark you BRAINLIEST >:DDDDDDDD
Alik [6]

Answer:

d..i think..he found plant cells

Explanation:

7 0
3 years ago
Read 2 more answers
A compound with the formula C6H14 was reacted with Cl2/light to give a mixture of 5 different monochlorinated products (not incl
allochka39001 [22]

Answer:

Hexane.

Explanation:

Hello!

In this case, since the general reaction of the compound C4H14 with chlorine is:

C_6H_{14}+Cl_2\rightarrow C_6H_{13}Cl+HCl

Which stands for a substitution chemical reaction in which one chlorine is able to replace one hydrogen and therefore hydrogen chloride gives off; we infer that the initial compound, C4H14, shows off the C_nH_{2n+2} formula characteristic of alkanes; in such a way, as it has six carbon atoms, we infer it is hexane.

Best regards!

6 0
3 years ago
A solution was prepared by dissolving 28.0g of KCL in 225g of water. Part A Calculate the mass percent ofKCL in the solution. Pa
Westkost [7]

Answer:

A. 11.1%

B. 0.0291

C. 1.57 M

D. 1.67 m

Explanation:

A.

Mass of KCl (solute): 28.0 g

Mass of water (solvent): 225 g

Mass of solution: 28.0 g + 225 g = 253 g

The mass percent of KCl is:

%KCl = (mass of KCl/mass of solution) × 100%

%KCl = (28.0 g/253 g) × 100%

%KCl = 11.1%

B.

The molar mass of KCl is 74.55 g/mol. The moles of KCl are:

28.0 g × (1 mol/74.55 g) = 0.376 mol

The molar mass of water is 18.02 g/mol. The moles of water are:

225 g × (1 mol/18.02 g) = 12.5 mol

The total number of moles is 0.376 mol + 12.5 mol = 12.9 mol.

The mole fraction of KCl is:

X(KCl) = moles of KCl / total moles

X(KCl) = 0.376 mol / 12.9 mol

X(KCl) = 0.0291

C.

The volume of the solution is 239 mL (0.239 L).

The molarity of KCl is:

M = moles of KCl / liters of solution

M = 0.376 mol / 0.239 L

M = 1.57 M

D.

The molality of KCl is:

m = moles of KCl / kilograms of solvent

m = 0.376 mol / 0.225 kg

m = 1.67 m

4 0
4 years ago
You must answer all questions to get credit for this assignment. Use the notes above and/or the textbook to help you find the an
Allisa [31]

Explanation:

(1).  It is known that in a reaction equation, reactants are placed or written on left hand side and products are written on the right hand side.

For example, N_{2} + 3H_{2} \rightarrow 2NH_{3}

Hence, in a reaction equation you start with the reactants and end up with the products.

(2).  The number of atoms in a reaction will remain the same because according to the law of conservation of mass, mass of reactants will be equal to the mass of products.

Therefore, number of atoms on the reactant side will be equal to the number of atoms on product side.

7 0
3 years ago
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