The mass of the solute required is 250.25 g.
<h3>What is the mass of the solute?</h3>
We know that the number of moles of the solute can be used to obtain the mass of the solute that is required. We can now try to find the mass of the solute that is required.
Concentration of the solution = 0.350M
Volume of the solution = 6.5 L
Number of moles of the solute = 0.350M * 6.5 L
= 2.275 moles
We now have the mass of the solute as;
2.275 moles * 110 g/mol
= 250.25 g
Th measured mass of the solute that we would have to use is 250.25 g.
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Missing parts;
A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?
Answer:
17.1 L
Explanation:
P1V1/T1 = P2V2/T2 T is in K
P1V1/T1 * T2/P2 = V2
735 * 7.31 / (45+273.15) * (55+ 273.15)/325 = V2
V2 = 17.1 L
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