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lorasvet [3.4K]
1 year ago
15

A sample of argon (Ar) gas has a volume of 7.31 L at a pressure of

Chemistry
1 answer:
Pie1 year ago
3 0

Answer:

17.1 L

Explanation:

P1V1/T1  =  P2V2/T2        T is in K

P1V1/T1 * T2/P2 = V2

735 * 7.31 / (45+273.15)  * (55+ 273.15)/325 = V2

V2 = 17.1 L

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Molar mass of hydrated compound = 250 g/mol

x/160 = 2/250

250x = 2 ×160

x= 2 × 160/250

x= 1.28 g

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