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lorasvet [3.4K]
2 years ago
15

A sample of argon (Ar) gas has a volume of 7.31 L at a pressure of

Chemistry
1 answer:
Pie2 years ago
3 0

Answer:

17.1 L

Explanation:

P1V1/T1  =  P2V2/T2        T is in K

P1V1/T1 * T2/P2 = V2

735 * 7.31 / (45+273.15)  * (55+ 273.15)/325 = V2

V2 = 17.1 L

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Answer:

\rho =1.96\frac{g}{L}

Explanation:

Hello there!

In this case, since this imaginary gas can be modelled as an ideal gas, we can write:

PV=nRT

Which can be written in terms of density and molar mass as shown below:

\frac{P}{RT} =\frac{n}{V} \\\\\frac{P}{RT} =\frac{m}{MM*V}\\\\\frac{P*MM}{RT} =\frac{m}{V}=\rho

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