Answer:
(A). The electric field strength inside the solenoid at a point on the axis is zero.
(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is
.
Explanation:
Given that,
Magnetic field = 2.0 T
Diameter = 5.0 cm
Rate of decreasing in magnetic field = 5.00 T/s
(A). We need to calculate the electric field strength inside the solenoid at a point on the axis
Using formula of electric field inside the solenoid

Electric field on the axis of the solenoid
Here, r = 0


The electric field strength inside the solenoid at a point on the axis is zero.
(B). We need to calculate the electric field strength inside the solenoid at a point 1.50 cm from the axis
Using formula of electric field inside the solenoid



Hence, (A). The electric field strength inside the solenoid at a point on the axis is zero.
(B). The electric field strength inside the solenoid at a point 1.50 cm from the axis is
.
When it rains, the growth aids in the soil drift
Explanation:
Formula to determine the critical crack is as follows.

= 1,
= 24.1
[/tex]\sigma_{y}[/tex] = 570
and, 
= 427.5
Hence, we will calculate the critical crack length as follows.
a = 
= 
= 
Therefore, largest size is as follows.
Largest size = 2a
= 
= 
Thus, we can conclude that the critical crack length for a through crack contained within the given plate is
.
Infrared rays are used in many forms of thermal technology. This is also used in weather reports to find the temperature of the surrounding areas.
Answer:
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