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2 years ago

A dilation of square ABCD centered at the origin with a scale factor of

Mathematics

1 answer:

Kisachek [45]2 years ago

5 0

Answer:

not sure

Step-by-step explanation: i just wanted the points

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The surface area of a sphere with radius R can be calculated using the formula S=4pi*r^2. Write a formula showing r's dependence

son4ous [18]

Step-by-step explanation:

your expression for the dependence of r on S is correct

4 0

2 years ago

The base of a expoential function can be a negative number true or false

Orlov [11]

Answer:

This would be false

Step-by-step explanation:

Exponents can't be negative

4 0

4 years ago

Read 2 more answers

Find the angle between the given vectors to the nearest tenth of a

pochemuha

Answer: 109.1 degrees

Step-by-step explanation:

To find the angle between the given vectors, we will use the formula below:

Cos(θ) = (U.V)/ |U|.|V|

Where

U = 13i - 8j

V = 2i + 9j

U.V = (2x13) + (-8×9)

U.V = 26 - 72

U.V = - 46

|U| = sqrt ( 13^2 + 8^2)

= sqrt ( 233) = 15.264

|V| = sqrt( 2^2 + 9^2)

= sqrt ( 85 ) = 9.22

Substitute all the value of the parameters into the formula

Cos ø = -46 / (15.3 × 9.2)

Cos ø = - 46 / 140.72

Cos Ø = - 32687

Find the cos inverse of the value

Ø = cos^-1( -32687)

Ø = 109.079 degrees

Therefore, the angle between the given vectors to the nearest tenth of a degree is 109.1 degrees

6 0

3 years ago

Look at the triangle show on the right. The Pythagorean Theorem states that the sum of the squares of the legs of a right triang

Vladimir [108]

Answer:

$cos^2\theta + sin^2\theta = 1$

Step-by-step explanation:

Given

$(\frac{b}{r})^2 + (\frac{a}{r})^2$

Required

Use the expression to prove a trigonometry identity

The given expression is not complete until it is written as:

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = (\frac{r}{r})^2$

Going by the Pythagoras theorem, we can assume the following.

a = Opposite
b = Adjacent
r = Hypothenuse

So, we have:

$Sin\theta = \frac{a}{r}$

$Cos\theta = \frac{b}{r}$

Having said that:

The expression can be further simplified as:

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1$

Substitute values for sin and cos

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1$ becomes

$cos^2\theta + sin^2\theta = 1$

3 0

4 years ago

A rectangle is to be inscribed in an isosceles right triangle in such a way that one vertex of the rectangle is the intersection

svet-max [94.6K]

Answer:

x = 2 cm

y = 2 cm

A(max) = 4 cm²

Step-by-step explanation: See Annex

The right isosceles triangle has two 45° angles and the right angle.

tan 45° = 1 = x / 4 - y or x = 4 - y y = 4 - x

A(r) = x* y

Area of the rectangle as a function of x

A(x) = x * ( 4 - x ) A(x) = 4*x - x²

Tacking derivatives on both sides of the equation:

A´(x) = 4 - 2*x A´(x) = 0 4 - 2*x = 0

2*x = 4

x = 2 cm

And y = 4 - 2 = 2 cm

The rectangle of maximum area result to be a square of side 2 cm

A(max) = 2*2 = 4 cm²

To find out if A(x) has a maximum in the point x = 2

We get the second derivative

A´´(x) = -2 A´´(x) < 0 then A(x) has a maximum at x = 2

5 0

3 years ago