Answer:
- C for question 1
- A for question 2
Step-by-step explanation:
First Question
What you need to do here is pick an answer that will result in a decrease. If you have something like 1.3 * e ^ (0.038 * t), what will happen when t = 20
P = 1.3 * e^(0.038*20) = 1.3*e^0.76 = 2.77 which is getting bigger not smaller.
So what you want is something like 1.3 * e^-0.76 = 0.67
So which question is configured that way?
It's either C or D. but which one? It cannot be D. 0.38 is far too big: it does not represent 3.8%
C does represent 3.8% as a decimal. It is the correct answer.
Answer: C
Second Question
Every time she sells a ticket, the total that she gets is 4 more than what she had before.
The variation is a direct one. It is y = k*x. But what is k? Is it 4 or is it 1/4?
Read the first sentence above. She gets 4 dollars more, not 1/4 of a dollar.
C and D are both wrong because those equations think she is getting 1/4 more.
B is wrong because it says that the relationship is inverse. It is not. It is direct.
The answer is A
Less, 5oz=141.7g
so 75g<5oz
Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.
<h3>What is the binomial distribution formula?</h3>
The formula is:
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem, we have that:
- There are 6 students, hence n = 6.
- There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.
The probability of one quote being chosen at least two times is given by:
![P(X \geq 2) = 1 - P(X < 2)](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20P%28X%20%3C%202%29)
In which:
P(X < 2) = P(X = 0) + P(X = 1).
Then:
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20C_%7B6%2C0%7D.%280.05%29%5E%7B0%7D.%280.95%29%5E%7B6%7D%20%3D%200.7351)
![P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B6%2C1%7D.%280.05%29%5E%7B1%7D.%280.95%29%5E%7B5%7D%20%3D%200.2321)
Then:
P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.
![P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20P%28X%20%3C%202%29%20%3D%201%20-%200.9672%20%3D%200.0328)
0.0328 = 3.28% probability that at least 2 of them choose the same quote.
More can be learned about the binomial distribution at brainly.com/question/24863377
Answer:
probability of landing on purple and pink. Find the missing probability. get ... numbered 1 through 5. Predict how many times out of 240 spins the spinner is most likely to stop on an odd number. odd ... Answer: red marbles. D. 10 total blue marbles green marbles. 1 2 2 2 2 ... You receive a less expensive prize if you spin and.
Step-by-step explanation: