What is the equation of the graphed line written in

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

4 0

Answer:

x = -3

Step-by-step explanation:

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Olivia has 680 to spend at a bicycle store for some new gear and biking outfits

stira [4]

What is the question

7 0

3 years ago

The ratio of the profit, material cost and production labour of an article is 5:7:13.

IRINA_888 [86]

Answer:

The cost of producing the article is -3500 (Negative cost)

Step-by-step explanation:

The given parameters are

The ratio of the profit to material cost to production labor = 5:7:13

The amount of the material cost = 840 + Labor cost

Let the total cost = X

Therefore, we have;

The fraction of the total cost that is material cost = 7/(5 + 7 + 13) = 7/25

Therefore, the material cost = 7/25 × X

The fraction of the total cost that is labor cost = 13/(5 + 7 + 13) = 13/25

Therefore, the labor cost = 13/25 × X

However, the amount of the material cost = 840 + Labor cost, which gives;

7/25 × X = 13/25 × X + 840

7/25 × X - 13/25 × X = 840

-6/25 × X= 840

X = 840/(-6/25) = 840×(-25/6) = -3500

The cost of producing the article = -3500.

8 0

3 years ago

30 POINTS

PtichkaEL [24]

Answer:

180 degrees per second.

Step-by-step explanation:

We have been given a graph that shows the distance covered by a tire or angular velocity of a tire with respect to the number of seconds (x).

Since we know that a tire is a circle and the measure of all the angles of a circle equals to 360 degrees.

We can see from our given graph that the tire completes one rotation in 2 seconds (2.5-0.5), so the distance covered by tire in two seconds will be 360 degrees. This means that the tire turns 360 degrees in each 2 seconds.

$\text{Degrees turned by tire in 2 seconds}=\frac{360^o}{2\text{ seconds}}$

As we are asked to find the degree change by tire per second so we will find the unit rate such that we will have 1 in our denominator. By dividing our numerator and denominator by 2 we will get,

$\text{Degrees turned by tire in every second}=\frac{180^o}{\text{ second}}$