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Sholpan [36]
3 years ago
9

X^2-3=0 solve for all real values of x

Mathematics
2 answers:
elena-s [515]3 years ago
7 0

Answer:

x = √3

x = - √3

Step-by-step explanation:

x^2 - 3 = 0          Add 3 to both sides

x^2 = 3               Take the square root of both sides.

sqrt(x^2) = sqrt(3)

x = +/- sqrt(3)

Remember that the - root is also a solution to the question. Also for this question don't put the - sign under the root sign. That is an entirely different question.

sineoko [7]3 years ago
3 0

Step-by-step explanation:

x²-3=0

x²=3

x=√3

<h2>stay safe healthy and happy.</h2>
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Which comparisons are true? Choose all that apply. A. 7.34 &gt; 7.304 B. 1.628 &gt; 1.63 C. 4.05 &lt; 4.055 D. 9.103 &lt; 9.13 E
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6 0
3 years ago
In Cos A = 0.4 Find The Value Of Cos 3 A.<br><br><br><br>Thenku ☃️<img src="https://tex.z-dn.net/?f=%20%5C%3A%20%5C%3A%20" id="T
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3 0
3 years ago
Read 2 more answers
Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

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1 year ago
I need help with algebra function notation
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What is the question
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