Answer:
We conclude that cheddar popcorn weighed less than 5.5 ounces.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ =5.5 ounces
Sample mean,
= 5.23 ounces
Sample size, n = 64
Alpha, α = 0.05
Sample standard deviation, σ = 0.24 ounce.
First, we design the null and the alternate hypothesis

We use One-tailed z test to perform this hypothesis.
Formula:

Putting all the values, we have

Now, 
Since,

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that cheddar popcorn weighed less than 5.5 ounces.
35,000 ft - 6,000 ft = 29,000 ft
The given coordinates are:
p1: (12,4) and p2: (-8,8)
Th x coordinate of the midpoint is calculated as follows:
Xmidpoint = (x1+x2) / 2 = (12+-8) / 2 = 4/2 = 2
The y coordinate of the midpoint is calculated as follows:
Ymidpoint = (y1+y2) / 2 = (4+8) / 2 = 12/2 = 6
Based on the above calculations, the midpoint of the segment with the given coordinates is (2,6)
A = -11
B= -12
This is because of how calculations work in negatives. Because they are both negative they work similarly to addition