All categories

2 years ago

If 25% of a number, n, is 6.25, what is 42% of n? A.10.50 B.2.625 C.1.5625 D.5.250

Mathematics

2 answers:

Marrrta [24]2 years ago

8 0

Answer: The answer would be A: 10.50

Step-by-step explanation: 6.25 x 4 since it’s 25% this will get you 25 you then take 42% of 25 and get 10.50

miss Akunina [59]2 years ago

7 0

Answer:

The answer is probably 10.50

(sorry if im wrong)

Step-by-step explanation:

You might be interested in

PLEASE HELP BEST ANSWER WILL GET BRAINLIEST

Alina [70]

Answer: Expression I & Expression II

Step-by-step explanation:

2n+n+3n+5 simplifies to 6n+5

8 0

3 years ago

Log2(y)=3log3(u)<br> log5(y)=2log(u) + 3log5(v)<br> Write y in terms of u and v

Gelneren [198K]

It’s attached there

Here

7 0

2 years ago

The perimeter of a rectangle

mina [271]

XZ=XY+YZ

JL=JK+KL

use the trigonometric values table or unit circle to calculate the expression

6 0

2 years ago

Stefania has a collection 1432 mp3s. Of those songs, 25% are rock songs and 55% are rap songs. How many songs are other types of

Katena32 [7]

Start answering here

7 0

2 years ago

A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A ran

mart [117]

Answer:

a) The 95% confidence interval would be given (0.070;0.121).

b) "increase the sample size n"

"decrease za/2 by decreasing the confidence"

Step-by-step explanation:

Notation and definitions

$X=48$ number of vehicles classified as sports utility.

$n=500$ random sample taken

$\hat p=\frac{48}{500}=0.096$ estimated proportion of vehicles classified as sports utility vehicles.

$p$ true population proportion of vehicles classified as sports utility vehicles.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

(a) Use a 95% confidence interval to estimate the proportion of sports utility vehicles in California. (Round your answers to three decimal places.)

The confidence interval would be given by this formula :

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.096 - 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.070$

$0.096 + 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.121$

And the 95% confidence interval would be given (0.070;0.121).

We are confident (95%) that about 7.0% to 12.1% of vehicles in California are classified as sports utility .

(b) How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy? (HINT: There are two answers. Select all that apply.)

For this case we just have two ways to increase the accuracy one is "increase the sample size n" since if we have a larger sample size the estimation would be more accurate. And the other possibility is "decrease za/2 by decreasing the confidence" because if we decrease the confidence level the interval would be narrower and accurate

7 0

2 years ago