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Pepsi [2]
3 years ago
11

Keisha had $54 when she went to a bookstore. She

Mathematics
2 answers:
storchak [24]3 years ago
4 0
54 - a = 12 i believe
Anna [14]3 years ago
3 0
It will be a: 54-a=12
This is because she started with 54 and ended with 12. You need to keep a in the middle since that’s the amount you spent to end up at 12. Have a good day :)
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Find m∠TUL.
pogonyaev

 

Step-by-step explanation:

Actual graph for this problem is attached below

m∠TUV = 167°

m∠TUL = (x + 11)°

m∠LUV = (11x)°

m∠TUV= m∠TUL+ m∠LUV

now plug in the angles for each

m∠TUV= m∠TUL+ m∠LUV

167= x+11 +11x

solve the equation for x

167= x+11 +11x\\167=11 +12x

Subtract 11 from both sides

156=12x

divide both sides by 12

x=13

m∠TUL = (x + 11)°

m∠TUL = (13+ 11)° = (24)°

answer:

24°

4 0
3 years ago
Round to the nearest tenth 6.2x+1.2=8.9
Anuta_ua [19.1K]

Answer:

x = 1.2...

Step-by-step explanation:

Start with the given equation and isolate the variable.

6.2x + 1.2 = 8.9

Subtract 1.2 from each side:

6.2x = 7.7

Divide each side by 6.2:

x = 1.2...

7 0
3 years ago
Can the sides of a triangle be in a ratio of: a 3:4:5
victus00 [196]

Yes. In fact 3:4:5 is a Pythagorean triple or simply right triangle where all sides are in \mathbb{Z}.

Hope this helps.

5 0
3 years ago
Read 2 more answers
Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number
Gnoma [55]

Sum/difference:

Let

x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}

This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

x = -15\sqrt{8}

if again we assume x to be rational, we have

\sqrt{8} = -\dfrac{x}{15}

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0
2 years ago
To rent a certain meeting room, a college charges a reservation fee of $31 and an additional fee of $7.40 per hour. The chemistr
Mamont248 [21]
T= # of rental hours
Reservation Fee= $31
Per Hour Fee= $7.40


Multiply number of hours rented by the cost per hour, add that total to the reservation fee. The total needs to be less than $97.60.


Res Fee + ($ per hr * # hrs) < $97.60

$31 + $7.40t < $97.60
subtract 31 from both sides

7.40t < 66.60
divide both sides by 7.40

t < 9


ANSWER: To spend less than $97.60, they need to rent the room less than 9 hours.

Hope this helps! :)
7 0
3 years ago
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