Answer:
the Kinetic Energy of the marble at the later point is 0.0007 J
Step-by-step explanation:
Given;
initial potential energy of the marble, P.E₁ = 0.0018 J
final potential energy of the marble, P.E₂ = 0.0011 J
At the initial starting point, the total mechanical energy is;
M.E = K.E + P.E
at the initial starting point, velocity = 0
M.E = 0 + P.E
M.E = P.E = 0.0018 J
At some point later, the total mechanical energy is;
M.E = P.E + K.E
0.0018 J = 0.0011 J + K.E
0.0018 J - 0.0011 J = K.E
0.0007 J = K.E
Therefore, the Kinetic Energy of the marble at the later point is 0.0007 J
First, isolate y in 7x-y=29 because 1 is y's coefficient.
7x-y=29
-y=29-7x
y=7x-29
Now, substitute 7x-29 for y in 7x+8y=20.
7x+8y=20
7x+8(7x-29)=20
7x+56x-232=20
Add all coefficients.
63x-232=20
Isolate x by adding 232 to both sides.
63x-232=20
63x=252
x=4
Now, substitute 4 for x in your first equation.
y=7x-29
y=7(4)-29
y=28-29
y=-1
Your answer would be (4,-1).
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Answer:
2.a)31°
b)135°
3.a)72°
Step-by-step explanation:
2a) Angles in a straight line add up to 180°
180-62=118°
since in an isosceles triangle base angles are equal 62÷2=31°
b)sum of interior angles=180(n-2)
180(8-2)=1080°
each angle is 1080÷8=135°
3.a) Exterior angle=360/n
=360÷5=72° each
I think you forgot to put in the image
Answer:
x = 1. y = -3
Step-by-step explanation:
Add the two equations together and notice that all terms containing y will disappear, leaving with
10x = 10 or x = 1
Using this value of x into either one of the equations, you'll get
4(1) + 3y = -5 ---> 3y = -9 or y = -3