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nignag [31]
3 years ago
15

. 6x – 3y = 15

Mathematics
1 answer:
yuradex [85]3 years ago
5 0

Answer:

x = 1. y = -3

Step-by-step explanation:

Add the two equations together and notice that all terms containing y will disappear, leaving with

10x = 10 or x = 1

Using this value of x into either one of the equations, you'll get

4(1) + 3y = -5 ---> 3y = -9 or y = -3

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(1+tanx)/(sinx+cosx)=secx
jek_recluse [69]

\frac{1+\tan x}{\sin x+\cos x}=\sec x is proved

<h3><u>Solution:</u></h3>

Given that,

\frac{1+\tan x}{\sin x+\cos x}=\sec x  ------- (1)

First we will simplify the LHS and then compare it with RHS

\text { L. H.S }=\frac{1+\tan x}{\sin x+\cos x}  ------ (2)

\text {We know that } \tan x=\frac{\sin x}{\cos x}

Substitute this in eqn (2)

=\frac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}

On simplification we get,

=\frac{\frac{\sin x+\cos x}{\cos x}}{\sin x+\cos x}

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Cancelling the common terms (sinx + cosx)

=\frac{1}{c o s x}

We know secant is inverse of cosine

=\sec x=R . H . S

Thus L.H.S = R.H.S

\frac{1+\tan x}{\sin x+\cos x}=\sec x

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